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elena-14-01-66 [18.8K]
3 years ago
9

A drop of gasoline has a mass of 22 mg and a density of 0.754 g/cm3. What is its volume in cubic centimeters?

Chemistry
1 answer:
ArbitrLikvidat [17]3 years ago
5 0
1.22 mg is the same as .022 grams. One gram equals 1000 mg. Convert mg to grams  by dividing mg by 1000mg/gm. Volume = mass over density. Volume equals .022 grams over .754 grams/cm3 which equals .029 or .03cm3. 2.weight in kg times gravity constant. Weight in newtons equals 10kg times 9.8m/s2 that equals 98 newtons. 
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I need an answer now please asap and you will me marked brainiest please it's missing I need it now.
valentina_108 [34]

Answer:

C. NaHCO3 → Na2CO3 + H2O + CO2

Explanation:

» For a balanced equation, the number of atoms of reactants and products must be equal.

» In equation C, the reactant side has one sodium atom while ptoduct side has 2 sodium atoms.

» The balanced equations mus be;

{ \rm{ 2NaHCO _{3(aq)} → Na _{2}CO _{3(s)}+ H _{2} O _{(l)} + }CO _{2(g)} }

7 0
2 years ago
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Calculate the ph of 0.375 l of a 0.18 m acetic acid-0.29 m sodium acetate buffer after the addition of 0.0090 mol of koh. assume
Iteru [2.4K]

To calculate the pH of this solution, we use the Henderson-Hasselbalch equation: 

pH = pKa + log ([A-]/[HA])

Where,

[A-] = Molarity of the conjugate base = CH3COO- = 0.29 M<span>
<span>[HA] = Molarity of the weak acid  = CH3COOH = 0.18 M</span></span>

pKa = dissociation constant of the weak acid = 4.75

When KOH is added to the buffer, the chemical reaction is:

CH3COOH + KOH = CH3COO-K+ + H2O

Therefore when 0.0090 mol KOH is added, 0.0090 mol acid is neutralized, and 0.0090 mol CH3COO- is produced.

[CH3COO-] = [0.0090 mol + 0.375 L (0.29 mol/L) ] / 0.375 L = 0.314 M

[CH3COOH] = [-0.0090 mol + 0.375 L (0.18 mol/L) ] / 0.375 L = 0.156 M

Going back to Henderson-Hasselbalch equation:

pH = 4.75 + log (0.314 / 0.156)

<span>pH = 5.054</span>

7 0
3 years ago
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How many valence electrons are transferred from nitrogen atom to potassium in the formation of the compound potassium nitride?
AlexFokin [52]
Answer:
            3 electrons are gained by one nitrogen atom in the formation of K₃N.

Explanation:

The reaction is as follow,

<span>                                       6 K + N</span>₂<span>    </span>→   <span> 2 K</span>₃<span>N
</span>
Oxidation of K,

                                       K     →     K⁺  +  1 e⁻
Or,
                                    6 K     →    6 K⁺  +  6 e⁻

In oxidation reaction potassium atom transfers one electron per atomn and six electrons per six atoms.

Reduction of N;
                                  N₂  +  6 e⁻    →    2 N³⁻

In reduction reaction one molecule of N₂ gains six electrons and 3 electrons per one atom
8 0
3 years ago
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Using the van der waals equation, the pressure in a 22.4 l vessel containing 1.50 mol of chlorine gas at 0.00 °c is ________ atm
Lana71 [14]

Answer is: the pressure in a vessel is 1.48 atm.

V(Cl₂) = 22.4 L; pressure of chlorine gas.

n(Cl₂) = 1.50 mol; amount of chlorine gas.

T = 0.00°C = 273.15 K; temperature.

a = 6.49 L²·atm/mol²; the constant a provides a correction for the intermolecular forces.

b = 0.0562 L/mol; value is the volume of one mole of the chlorine gas.

R = 0.08206 L·atm/mol·K, universal gas constant.

Van de Waals equation: (P + an² / V²)(V - nb) = nRT.

(P +  6.49 L²·atm/mol² · (1.5 mol)² / (22.4 L)²) · (22.4 L - 1.5 mol·0.0562 L/mol) = 1.5 mol · 0.08206 L·atm/mol·K · 273.15 K.

(P +  6.49 L²·atm/mol² · (1.5 mol)² / (22.4 L)²) = (1.5 mol · 0.08206 L·atm/mol·K · 273.15 K) ÷ (22.4 L - 1.5 mol · 0.0562 L/mol).

P + 0.029 atm = 33.62 L·atm ÷ 22.31 L.

P = 1.507 atm - 0.029 atm.

P = 1.48 atm; the pressure.

7 0
3 years ago
Use the drop-down menus to identify the effect of each mutation.
krek1111 [17]

Answer:

1 neutral

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3 harmful

Explanation:

7 0
4 years ago
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