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Alexeev081 [22]
3 years ago
14

How to simplify √128x^3y^4 ?

Mathematics
1 answer:
Serjik [45]3 years ago
8 0

\sqrt{128x^{3} y^{4} }  = [tex]\sqrt{8*8*2*x*x*x*y*y*y*y}

Take the perfect squares out the expression to simplify

8xy^2\sqrt{2x}

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Which statement describes the end behavior of the exponential function f(x) = 2x – 3?
charle [14.2K]
The <u>correct answer</u> is:

As x→-∞, y→-3.
As x→∞, y→∞.

Explanation:

As our values of x get further into the negative numbers, the value of 2ˣ will approach 0.  This is because raising a number to a negative exponent "flips" the number below the denominator and raises it to a power; we end up with smaller and smaller fractions, eventually so small that they nearly equal 0.  

This will make the value of the function 0-3=-3.

As x gets larger and larger (towards ∞), the value of y, 2ˣ, continues to grow as well.  Since it continues to grow exponentially, we say the value approaches ∞.
3 0
3 years ago
Read 2 more answers
A pipe that's 36 inches long needs to be cut into 2 and one forth inches long pieces. how may pieces can be cut from this length
PolarNik [594]
16 pieces may be cut. This is because we need to divide 36 by 2 and 1/4 to find how many pieces hat can be cut. First, we need to change everything into a fraction (or improper fraction). 2 and 1/4 = 9/4 (if you need help trying to find out how to get this, just ask). Then, since we are doing division, we flip the 9/4 around to get 4/9. 36 times (it's not dividing anymore since we flipped the 9/4) 4/9 = 16 pieces. I hope this helps! :D
7 0
4 years ago
What is the distance between the points (7, −4) and (7, 9)?
AlexFokin [52]
The answer to this question is C) 13

7 0
4 years ago
In a class 28 of students, 5 have a cat and 21 have a dog. There are 4 students who do not have a cat or a dog. What is the prob
Sergeeva-Olga [200]

Answer:

15 have only a dog

5 have a dog and a cat

9 have only a cat

Step-by-step explanation:

20 + 14 = 34, there there are only 29 students, so 34 - 29 or 5 have both a dog and a cat

15 have only a dog

5 have a dog and a cat

9 have only a cat

6 0
3 years ago
R/12=1 9/10<br><br> Solve for R.
Marianna [84]
Let's first turn 1 9/10 into an improper fraction, which is 19/10

so if R/12 equa;s 19/10, cross multiply

10r equals 228

divide both sides by 10, you get r= 22.8
7 0
3 years ago
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