100, how ever many zeros are in front of the number just count those and you'll get your answer
Answer:
7 x 3/9 = 21/9 = 2.33
11 x 2/3 = 22/3 = 7.33
4/9 x 3/8 = 4/9 x 3 / 8 = 4/3/8 = 1/6
7/9 x 4/5 = 7
/9 ⋅ 4/5 = 28/9/5 = 28/45
1 1/15 x 1/3 = 0.35
It will be the last option.
Answer:
21.19% eat less than 10 pieces of candy on halloween
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 14, \sigma = 5](https://tex.z-dn.net/?f=%5Cmu%20%3D%2014%2C%20%5Csigma%20%3D%205)
What percentage eat less than 10 pieces of candy on halloween
This is the pvalue of Z when X = 10.
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{10 - 14}{5}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B10%20-%2014%7D%7B5%7D)
![Z = -0.8](https://tex.z-dn.net/?f=Z%20%3D%20-0.8)
has a pvalue of 0.2119
21.19% eat less than 10 pieces of candy on halloween