Let the numbers be x&y
X+y=109
Taking a as the smallest number we multiply by 4
So according to the question you will have this equation
Y(as the largest number) -4x=4. Y-4x=4
Then find y
Y=4x+4
Substitute y on the first equation to get a
X+y=109
X+4x+4=109
X=21
21+y=109
Y=88
HOPE IT HELPS PLS MARK AS BRAINLIEST
July - august is your answer
Answer:
2.28% probability that a person selected at random will have an IQ of 110 or higher
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a person selected at random will have an IQ of 110 or higher?
This is 1 subtracted by the pvalue of Z when X = 110. So



has a pvalue of 0.0228
2.28% probability that a person selected at random will have an IQ of 110 or higher
Answer:
Step-by-step explanation:
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