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Neko [114]
3 years ago
7

On a scale drawing with a scale of 1 cm: 3 m , the height of a tree is 5 cm. How tall is the actual tree?

Mathematics
2 answers:
Neko [114]3 years ago
8 0
In 3 metres there are 300 centimetres. Each centimetre on the scale is 300 centimeters, or a ratio of 1:300. The tree is 5 centimetres on the scale. Each centimeter on the scale is 300 centimetres, therefore 5 centimetres on the scale is 1500 centimetres. 1500 centimetres is equal to 15 metres.
Helga [31]3 years ago
5 0
1cm: 3cm
X both by 5
5cm:15cm the actual tree would be 15 meters
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Read 2 more answers
don walked 3 3/5 miles on Friday, 3.7 miles on saturday, and 3 5/8 miles on sunday. list the distances from least to greatest
astraxan [27]

Solution:

we are given that

Don walked 3 3/5 miles on Friday

It can be re-written as

3\frac{3}{5}miles=\frac{18}{5}= 3.6miles

3 5/8 miles on sunday.

It can be re-written as

3\frac{5}{8}miles=\frac{29}{8}= 3.625miles

an d He walk 3.7 miles on satarday.

The distances from least to greatest is  3.6, 3.625, 3.7

or

The distances from least to greatest is  3\frac{3}{5}miles, 3\frac{5}{8}miles, 3.7 miles.

8 0
3 years ago
You need 660 mL of a 40% alcohol solution. On hand, you have 35% alcohol mixture. You also have a 95% alcohol mixture. How much
ozzi

Answer:

A. 605 mL of the 35% solution

B. 55 mL of the 95% solution

Step-by-step explanation:

It is given that, you need 660 mL of a 40% alcohol solution. On hand, you have 35% alcohol mixture. You also have a 95% alcohol mixture.

Let x and y be the amount of 35% alcohol solution and 95% alcohol solution (in mL) respectively.

So,

Amount equation: x+y=660        ...(1)

Alcohol equation : 0.35x+0.95y=0.40(660)\Rightarrow 0.35x+0.95y=264     ...(2)

On solving (1) and (2), we get

0.35(660-y)+0.95y=264

231-0.35y+0.95y=264

0.6y=264-231

y=\dfrac{33}{0.6}

y=55

Now, substitute y=55 in (1).

x+55=660  

x=660-55  

x=605  

Therefore, we need 605 mL of the 35% solution  and 55 mL of the 95% solution.

4 0
3 years ago
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