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RUDIKE [14]
3 years ago
12

If you sleep an average of 7.5 hours each night, how many hours do you sleep in a year?

Mathematics
2 answers:
satela [25.4K]3 years ago
5 0

Answer:

\boxed{\sf 2737.5 \ hours}

Step-by-step explanation:

The average is 7.5 hours of sleep each night.

There are 365 nights in 1 year.

\sf Multiply \ the \ value \ by \ 365.

7.5 \times 365

2737.5

Alik [6]3 years ago
4 0

Answer:

2,737 hours for a normal year, 2,745 if it is a leap year.

Step-by-step explanation:

Because there 365 days in a year, you should multiply the amount you sleep every day (7.5) by the number of days in a year (365)

7.5*365

Multiply 7.5 by 365 to get

2,737.5

Every year you will sleep 2,737 hours if you sleep 7.5 hours each day.

(If it is a leap year, just change 365 to 366 which will give you 2,745 hours)

I hope this helps. If you have any follow-up questions, feel free to ask.

Have a great day! :)

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Answer:

-9.2

Step-by-step explanation:

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Solve the equality, - (7c-18)-2c>0
Gwar [14]
(7c-18)-2c>0

group like terms: 7c-2c-18>0

add similar elements: 7c-2c=5c
5c-18+18>0+18

Add 18 to both sides
5c-18+18>0+18

simplify
5c>18

divide both sides by 5
5c÷5>18/5

simplify
c>18/5
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3 years ago
In statistics, what term means "a numerical range around a sample mean accompanied with a statement of how confident one is that
Alex Ar [27]

Answer:

Confidence Interval for the mean

Step-by-step explanation:

Confidence interval is made using the observations of a <em>sample</em> of data obtained from a population, so it is constructed in such a way, that, with a certain <em>level of confidence </em>(this is the statement mentioned in the question), that is, one could have a percentage of probability that the interval, or range around the value obtained, frequently 95%, contains the true value of a population parameter (in this case, the population mean).  

It is one way to extract information from a population using a sample of it. This kind of information is what inference statistic is always looking for.

An <u>approximation</u> about how to construct this interval or range:

  1. Select a random sample.
  2. For the specific case of a <em>mean</em>, you need to calculate the mean of the <em>sample </em>(sample mean), and, if standard deviation is unknown or not mentioned, also calculate the sample standard deviation.
  3. With this information, and acknowledged that these values follows a standard normal distribution (a normal distribution with mean 0 and a standard deviation of 1), represented by random variable Z, one can use all this information to calculate a <em>confidence interval for the mean</em>, with a certain confidence previously choosen (for example, 95%), that the population mean must be in this interval or <em>range around this sample mean.</em>

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3 years ago
An expression is shown below:
olganol [36]

Answer:

An expression is shown below:

10n³− 15n² + 20xn² − 30xn

Part A: Rewrite the expression so the GCF is factored completely. (4 points)

10n³− 15n² + 20xn² − 30xn

2*5*n*n*n-5*3*n*n+2*5*2*x*n*n-2*5*3*x*n

<u>Greatest</u><u> </u><u>common</u><u> </u><u>factor</u><u>=</u><u>5</u><u>*</u><u>n</u><u>=</u><u>5</u><u>n</u>

Part B: Rewrite the expression completely factored. Show the steps of your work.

Solution given;

10n³− 15n² + 20xn² − 30xn

5n(2n²-3n+4xn-6x)

5n(2n²+4xn-3n-6x)

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<u>5n(n+2x)(2n-3</u>)

7 0
3 years ago
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Evaluate each expression for s=4 and t=8<br> 1) (25)^2t<br> 2) 2st^2-5^2<br> 3) 2s^2-t^3/16
stepladder [879]

Answer:

<u>1.</u> 2.328×10^{22}

<u>2.</u> 487

<u>3.</u> 30.52  OR  0 (see explanation↓)

Step-by-step explanation:

<u>1.</u>(25)^{2t}

(sub for t=8)

=25^{2*8}

=25^{16}

=2.328×10^{22}

<u>2.</u>2st^{2} -5^{2}

(sub for s=4 and t=8)

=2×4×8^{2}-5^{2}

=512-25

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<u>3.</u>2s^{2} -t^{3/16} (the equation is not clear so I will do 2s^{2} -\frac{t^{3} }{16} as well)

<u>FOR</u> 2s^{2} -t^{3/16}

(sub s=4 and t=8)

=2×4^{2}-8^{3/16}

=32-1.476826146

=30.52 (to the nearest 2 decimal place)

<u>FOR</u> 2s^{2} -\frac{t^{3} }{16}

(sub s=4 and t=8)

=2×4^{2}-\frac{8^{3} }{16}

=32-32

=0

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