Question

SOMEONE HELP PLEASE

Answer 1

Answer:

So the correct answer is option B- ( b - a )

Step-by-step explanation:

Given that M and N are the mid-points of RT and ST.

We are to find the length of MN.

As shown in the figure,

the co-ordinates of the point T are (2c, 2d),

the co-ordinates of the point S are (2b, 0),

and

the co-ordinates of the point R are (2c, 2d).

Since M is the mid-point of TR, so the co-ordinates of M are

$\left(\dfrac{2c+2a}{2},\dfrac{2d+0}{2}\right)$=(c+a,d).

Also, N is the mid-point of TS, the co-ordinates of N are

$\left(\dfrac{2c+2b}{2},\dfrac{2d+0}{2}\right)$=c+b,d)(.

Therefore, the length of the line segment MN calculated using distance formula will be

MN=$\sqrt{(c+b-c-a)^2+(d-d)^2}=\sqrt{(b-a)^2}$=b-a.

Thus, the required length of MN is (b - a) units.

Option (B) is correct.

Answer 2

I have this same question, can anyone answer it?