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-Dominant- [34]
3 years ago
8

Look at the picture of a scaffold used to support construction workers. The height of the scaffold can be changed by adjusting t

wo slanting rods, one of which, labeled PR, is shown:
A support structure is shown in which a right triangle PQR is formed with the right angle at Q. The length of PQ is shown as 14 feet, and the length of QR is shown as 9 feet..

Part A: What is the approximate length of rod PR? Round your answer to the nearest hundredth. Explain how you found your answer stating the theorem you used. Show all your work. (5 points)

Part B: The length of rod PR is adjusted to 18 feet. If width PQ remains the same, what is the approximate new height QR of the scaffold? Round your answer to the nearest hundredth. Show all your work. (5 points)
Mathematics
1 answer:
Vikki [24]3 years ago
8 0

Answer:

Triangle PQR is a right triangle therefore you can use the pythagorean theorem to find the length of PR which is the same as the hypothenuse

Step-by-step explanation:

Theorem:

(QP)² + (QR)² = (PR)²

(6)² + (14)² = 232 ⇒  (PR)² = 232  then PR = √232 = 15.23

If PR is adjusted to 16 feet then we use the Pythagorean theorem again to find the height QR

(QR)² + (14)² = (16)²

(QR)² = 256 - 196 = 60 ⇒ QR = √60 = 7.75.

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Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.
Hatshy [7]

Answer:

The change in the area of the rectangle is 0 square feet

Step-by-step explanation:

To solve this problem we have to calculate the area of ​​the two rectangles that give us

first we have to know the formula to calculate the area of ​​a rectangle

a = area

l = length  = 12ft

w = width = 5ft

a = l * w

we replace the known walues

a = 12ft * 5ft

a = 60ft²

we do the same with the other rectangle, but first we have to calculate its sides

w = 5ft - (5ft * 20/100)

w = 5ft - 1ft

w = 4ft

l = 12ft + (12ft * 25/100)

l = 12ft + 3ft

l = 15ft

a2 = 15ft * 4ft

a2 = 60ft²

to calculate the change in the area we subtract (a - a2)

a - a2 =

60ft² - 60ft² = 0ft²

3 0
3 years ago
What is 1 and five eights plus 2 and threee sixteenths plus 7 and one half?
Helen [10]

Answer:

11 and 5/16

Hope this answers your question

8 0
3 years ago
Read 2 more answers
Find an equation in standard form for the hyperbola with vertices at (0, ±9) and foci at (0, ±11)
Katen [24]

Answer:

\frac{y^{2} }{81} -\frac{x^{2} }{40} }=1 is standard equation of hyperbola with vertices at (0, ±9) and foci at (0, ±11).

Step-by-step explanation:

We have given the vertices at (0, ±9) and foci at (0, ±11).

Let (0,±a)  = (0,±9) and (0,±c)  = (0,±11)

The standard equation of parabola is:

\frac{y^{2} }{a^{2} } -\frac{x^{2} }{b^{2} }=1

From statement, a  = 9

c² = a²+b²

(11)²  = (9)²+b²

121-81  = b²

40  = b²

Putting the value of a² and b² in standard equation of parabola, we have

\frac{y^{2} }{81} -\frac{x^{2} }{40} }=1 which is the answer.

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3 years ago
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777dan777 [17]
-17 is the correct answer:)
8 0
3 years ago
Diamond is playing a game. In the game she has to spin a spinner
harina [27]

Answer:

1/16

Step-by-step explanation:

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