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VLD [36.1K]
3 years ago
7

If same earns $2 more, he’ll have $24. How much does he have to start out with?

Mathematics
2 answers:
xxTIMURxx [149]3 years ago
8 0

Answer:2

Step-by-step explanation:

julsineya [31]3 years ago
7 0

Answer: 22

Step-by-step explanation:

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88, 4x, 12x solve for x
vredina [299]
Wait what....? No equal signs or inequalities...?
7 0
3 years ago
compute the projection of → a onto → b and the vector component of → a orthogonal to → b . give exact answers.
Nina [5.8K]

\text { Saclar projection } \frac{1}{\sqrt{3}} \text { and Vector projection } \frac{1}{3}(\hat{i}+\hat{j}+\hat{k})

We have been given two vectors $\vec{a}$ and $\vec{b}$, we are to find out the scalar and vector projection of $\vec{b}$ onto $\vec{a}$

we have $\vec{a}=\hat{i}+\hat{j}+\hat{k}$ and $\vec{b}=\hat{i}-\hat{j}+\hat{k}$

The scalar projection of$\vec{b}$onto $\vec{a}$means the magnitude of the resolved component of $\vec{b}$ the direction of $\vec{a}$ and is given by

The scalar projection of $\vec{b}$onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|}$

$$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\sqrt{1^2+1^1+1^2}} \\&=\frac{1^2-1^2+1^2}{\sqrt{3}}=\frac{1}{\sqrt{3}}\end{aligned}$$

The Vector projection of $\vec{b}$ onto $\vec{a}$ means the resolved component of $\vec{b}$ in the direction of $\vec{a}$ and is given by

The vector projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|^2} \cdot(\hat{i}+\hat{j}+\hat{k})$

$$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\left(\sqrt{1^2+1^1+1^2}\right)^2} \cdot(\hat{i}+\hat{j}+\hat{k}) \\&=\frac{1^2-1^2+1^2}{3} \cdot(\hat{i}+\hat{j}+\hat{k})=\frac{1}{3}(\hat{i}+\hat{j}+\hat{k})\end{aligned}$$

To learn more about scalar and vector projection visit:brainly.com/question/21925479

#SPJ4

3 0
1 year ago
(10x - 4)=20<br> Question: What value of x makes the equation true
liraira [26]

Answer:

x = 10.4

Step-by-step explanation:

1. Multiply each side by 5 to remove it as a fraction

2. it cancels out on the left leaving 10x - 4 = 100

3. Add 4 to each side canceling it out on the left and leaving 10x = 104

4. Divide each side by 10 to get x by itself

5. 10x/100 = 104/10

6. x = 10.4

4 0
3 years ago
Which explains how to find the quotient of the division below? Negative 3 and one-third divided by StartFraction 4 over 9 EndFra
Ulleksa [173]

Answer:

(B) Write Negative 3 and one-third as Negative StartFraction 10 over 3 EndFraction, and find the reciprocal of StartFraction 4 over 9 EndFraction as StartFraction 9 over 4 EndFraction. Then, rewrite Negative 3 and one-third divided by StartFraction 4 over 9 EndFraction as Negative StartFraction 10 over 3 EndFraction times StartFraction 9 over 4 EndFraction. The quotient is Negative 7 and StartFraction 6 over 12 EndFraction = Negative 7 and one-half.

Step-by-step explanation:

To find the quotient of the division:

-3\dfrac13 \div \dfrac49

Step 1: \text{Write}$ $ -3\dfrac13$ as $ -\dfrac{10}{3}

-3\dfrac13 \div \dfrac49 =  -\dfrac{10}{3} \div \dfrac49

Step 2: Find the reciprocal of  \dfrac94

-\dfrac{10}{3} \times \dfrac94\\=-7\dfrac12

4 0
3 years ago
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There were 17 students reading a book. Eight students have finished. How many students are still reading the book?
ziro4ka [17]

Answer:

9

Step-by-step explanation:

3 0
3 years ago
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