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3 years ago

A triangle has two sides of lengths 8 and 10. what value could the length of the 3rd side be?

Mathematics

1 answer:

harkovskaia [24]3 years ago

8 0

Answer:

Step-by-step explanation:

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Help please? I would love if you could answer quickly.

Darina [25.2K]

Answer:

Step-by-step explanation:

$\frac{5}{9}(194-32)=90$

5 0

2 years ago

Simplify <br> 1/3n (-6+27m-51p)

marishachu [46]

1/3n * -6 = -2n
1/3n * 27m = 9nm
1/3n* -51p = -17np
-2n + 9nm - 17np

7 0

2 years ago

Read 2 more answers

Use algebra to simplify the expression before evaluating the limit. In particular, factor the highest power of n from the numera

bija089 [108]

Answer:

a) {2/n²-7/n+9}/{8+2/n-6/n²}

b) 9/8

c) The sequence converges

Step-by-step explanation:

Given the limit of the function

limn→[infinity]2−7n+9n²/8n²+2n−6

To simplify the function given, we will have to factor out the highest power of n which is n² from the numerator and the denominator. The function will then become;

2−7n+9n²/8n²+2n−6

= n²{2/n²-7/n+9}/n²{8+2/n-6/n²}

The n² at the numerator will then cancel out the n² at the denominator to have resulting simplified equation as;

{2/n²-7/n+9}/{8+2/n-6/n²}

Evaluating the limit of the resulting equation will give;

limn→[infinity] {2/n²-7/n+9}/{8+2/n-6/n²}

Note that limn→[infinity] a/n = 0 where a is any constant.

Therefore;

limn→[infinity] {2/n²-7/n+9}/{8+2/n-6/n²}

= (0-0+9)/(8+0-0)

= 9/8

Since the limit of the sequence gives a finite value which is 9/8, thus the sequence in question is a convergent sequence.

The limit of a sequence only diverges if the limit of such sequence is an infinite value.

5 0

3 years ago

If 8 gallons of gas cost $40, how much does 10 gallons of gas cost

insens350 [35]

8 costs 40 so 10 costs | 40 / 8 = ( 5*2=10) So your answer is 50 Dollars.

5 0

2 years ago

For what value of constant c is the function k(x) continuous at x = 0 if k =

nlexa [21]

The value of constant c for which the function k(x) is continuous is zero.

<h3>What is the limit of a function?</h3>

The limit of a function at a point k in its field is the value that the function approaches as its parameter approaches k.

To determine the value of constant c for which the function of k(x) is continuous, we take the limit of the parameter as follows:

$\mathbf{ \lim_{x \to 0^-} k(x) = \lim_{x \to 0^+} k(x) = 0 }$

$\mathbf{\implies \lim_{x \to 0 } \ \ \dfrac{sec \ x - 1}{x}= c }$

Provided that:

$\mathbf{\implies \lim_{x \to 0 } \ \ \dfrac{sec \ x - 1}{x}= \dfrac{0}{0} \ (form) }$

Using l'Hospital's rule:

$\mathbf{\implies \lim_{x \to 0} \ \ \dfrac{\dfrac{d}{dx}(sec \ x - 1)}{\dfrac{d}{dx}(x)}= \lim_{x \to 0} sec \ x \ tan \ x = 0}$

Therefore:

$\mathbf{\implies \lim_{x \to 0 } \ \ \dfrac{sec \ x - 1}{x}=0 }$

Hence; c = 0

Learn more about the limit of a function x here:

brainly.com/question/8131777

#SPJ1

5 0

1 year ago