A=11. to graph it plot an open circle on 11 and go right
Answer:
8
Step-by-step explanation:
Height, h = 17
Let :
Width = x
Length = 2x + 4
Volume = 2720 in³
Volume of rectangular prism = Length * width * height
2720 = 17 * x * (2x + 4)
2720 = 34x² + 68x
34x² + 68x - 2720 = 0
x² + 2x - 80 = 0
x² + 10x - 8x - 80 = 0
x(x + 10) - 8(x + 10)
(x + 10) = 0 or (x - 8) = 0
X = - 10 or x = 8
Width can't be negative
Hence, width, x = 8
Answer:
135
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Step-by-step explanation:
<u>Step 1: Define expression</u>
3³ · (12 - 2) ÷ 2
<u>Step 2: Evaluate</u>
- Exponents: 27 · (12 - 2) ÷ 2
- Subtract: 27 · 10 ÷ 2
- Multiply: 270 ÷ 2
- Divide: 135
Answer:
Step-by-step explanation:
To find how many solutions that they have, we must set both equations equal to each other as such:
-3x = -3x + 1
0 = 1, which isn't true
The system has zero solutions, I know this because when I solve the system of equation, I get that 0 =1 which isn't true
Hope that helps!
Answer:
t = 6.67 seconds
Step-by-step explanation:
Given that,
The distance of Moon from Earth, ![d=2.4\times 10^5\ miles](https://tex.z-dn.net/?f=d%3D2.4%5Ctimes%2010%5E5%5C%20miles)
The speed of the spacecraft, ![v=3.6\times 10^4\ miles/hour](https://tex.z-dn.net/?f=v%3D3.6%5Ctimes%2010%5E4%5C%20miles%2Fhour)
We need to find the time it take this spacecraft to fly to the moon from earth. Let the time is t.
We know that,
Speed = distance/time
![t=\dfrac{d}{v}\\\\t=\dfrac{2.4\times 10^5}{3.6\times 10^4}\\\\t=6.67\ s](https://tex.z-dn.net/?f=t%3D%5Cdfrac%7Bd%7D%7Bv%7D%5C%5C%5C%5Ct%3D%5Cdfrac%7B2.4%5Ctimes%2010%5E5%7D%7B3.6%5Ctimes%2010%5E4%7D%5C%5C%5C%5Ct%3D6.67%5C%20s)
So, the required time is equal to 6.67 seconds.