Question

The gcf of two numbers is 170. neither number is divisible by the other. what is the smallest these two numbers could be? (prime factorization of 170 = 2 x x 5 x 17)
please help!!

Answer 1

Answer:

$340$

Step-by-step explanation:

Given: GCF of two numbers is $170$. neither number is divisible by the other.

To Find: smallest of these two number.

Solution:

As GCF of two numbers is $170$, both number are divisible by $170$.

Prime factor of $170$ $=2\times5\times17$

multiples of $170$ are $1\times2\times5\times17=170$

                                           $2\times2\times5\times17=340$

                                           $3\times2\times5\times17=510$

GCF of all three multiples is $170$,

Here $340$ and $510$ are the two multiples whose GCF is $170$ and neither is divisible by other

Hence the smallest of two is $340$, the answer is $340$