The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.
Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>
We calculate the cross product as a determinant of (i,j,k) and the normal products
i j k
5 -1 -6
1 1 1
=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>
Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0
Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.
Answer:
$265.65
Step-by-step explanation:
Given :
WACC: 9.00%
Year 0 1 2 3 Cash flows (-$1,000) $500 $500 $500
The NPV is calculated thus :
Initial cashflow + Σ additional cash flows / (1 + r)
Rate, r = 9% = 0.09
(1 + r) = (1 + 0.09) = 1.09
NPV = - 1000 + (500 / (1.09)¹ + (500 / 1.09)² + (500 / (1.09)³
NPV = - 1000 + 458.71559 + 420.83999 + 386.09174
NPV = 265.64732
NPV = 265.65 (2 DECIMAL PLACES)
Answer:
so x = 20 , y = -21 , which is in quad IV
r^2= 400+441 = 841
r = √841 = 29
then cos Ø = 20/29
sec Ø = 29/20 = 1.45
please mark me as the brainliest answer and please follow me for more answers to your questions.
This is easy! Just use the point-slope form:
Plug in the values:
-1 - 4 = m(2 - (-3))
Combine like terms
-5 = 5m
Divide both sides by 6
m = 5/-5 or
m = -1
