Answer:
y = (1/2)(x + 4)(x + 1)(x - 3)
Step-by-step explanation:
Since this graph begins in Quadrant III and continues growing in Quadrant I, and has three roots/zeros, we know immediately that it's a cubing function and can confidently write out
y = d(x - a)(x - b)(x - c) as one general form of the cubing function.
In this particular case we have:
y = d(x + 4)(x + 1)(x - 3) (where the '4' comes from the x-intercept (-4, 0) )
From the graph we know that y = -6 when x = 0, and therefore:
-6 = d(0 + 4)(0 + 1)(0 - 3), or -6 = d(-12), leading to d = 1/2
Then our tentative equation (above) becomes y = (1/2)(x + 4)(x + 1)(x - 3)
First, lets create a equation for our situation. Let

be the months. We know four our problem that <span>Eliza started her savings account with $100, and each month she deposits $25 into her account. We can use that information to create a model as follows:
</span>

<span>
We want to find the average value of that function </span>from the 2nd month to the 10th month, so its average value in the interval [2,10]. Remember that the formula for finding the average of a function over an interval is:

. So lets replace the values in our formula to find the average of our function:
![\frac{25(10)+100-[25(2)+100]}{10-2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B25%2810%29%2B100-%5B25%282%29%2B100%5D%7D%7B10-2%7D%20)



We can conclude that <span>the average rate of change in Eliza's account from the 2nd month to the 10th month is $25.</span>
Complete Question
A psychologist has designed an index to measure the social perceptiveness of elementary school children. The index is based on ratings of a child's responses to questions about a set of photographs showing different social situations. A random sample of 16 elementary school children was chosen, and their index measurements were recorded. Assume that the index measure in the population is normally distributed. The 95% confidence interval created from this data is (56.29, 65.09). This interval indicates:__________.Choose one or more:
a. The average index of elementary school children must be 60.69.
b. The standard deviation of the sample is about 10% smaller than the population standard deviation.
c. That if we take many samples from this population 95% of them will have a sample mean between 56.29 and 65.09.
d. 95% of all elementary school children in this district have indices between 56.29 and 65.09.
e. 4.40 is 95% of the true average of the index for all elementary school children.
f. We are 95% confident that the average index for all elementary school children is between 56.29 and 65.09.
Answer:
The correct option is a and f
Step-by-step explanation:
From the question we are told that
The sample size is n = 16
The 95% confidence interval is (56.29, 65.09)
Generally the sample mean(average index of elementary school children) is mathematically represented as

=> 
Answer:
b)

Step-by-step explanation:
<u>Step(i)</u>:-
Given quadratic equation ax² + bx + c = 0
<u>step(ii)</u>:-
ax² + bx = -c
<u>Step(iii):</u>-
Dividing 'a' on both sides , we get


<u><em>Step(iv)</em></u>:-
Adding
on both sides , we get
