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kirill115 [55]
3 years ago
15

Geometry math question no Guessing and Please show work thank you

Mathematics
1 answer:
Ede4ka [16]3 years ago
5 0

The sum of Supplementary angle =180 degrees

(2x+3)⁰ +(3x+2)⁰=180⁰

adding like terms

5x+5=180

5x=180-5

5x=175

x=175/5 =35 degrees

so the two angles are :

(2x+3)⁰ =2*35 +3 = 73⁰

(3x+2)⁰=3*35 +2 =105+2 = 107⁰

so correct option is D , 73⁰ and 107⁰

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PLEASE HELP
uranmaximum [27]

The coordinate for A, B, C, and D: (Current coordinates)

A: (-1, 4)

B: (-5, 8)

C: (-5, 4)

D: (-4, 2)

Once we reflect acorss the y-axis the coordinates become:

A': (1, 4)

B': (5, 8)

C': (5, 4)

D': (4, 2)

In this situation the coordinates just become positive.

I hope this helps!

5 0
3 years ago
Evaluate c (y + 7 sin(x)) dx + (z2 + 9 cos(y)) dy + x3 dz where c is the curve r(t) = sin(t), cos(t), sin(2t) , 0 ≤ t ≤ 2π. (hin
saw5 [17]
Treat \mathcal C as the boundary of the region \mathcal S, where \mathcal S is the part of the surface z=2xy bounded by \mathcal C. We write

\displaystyle\int_{\mathcal C}(y+7\sin x)\,\mathrm dx+(z^2+9\cos y)\,\mathrm dy+x^3\,\mathrm dz=\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r

with \mathbf f=(y+7\sin x,z^2+9\cos y,x^3).

By Stoke's theorem, the line integral is equivalent to the surface integral over \mathcal S of the curl of \mathbf f. We have


\nabla\times\mathbf f=(-2z,-3x^2,-1)

so the line integral is equivalent to

\displaystyle\iint_{\mathcal S}\nabla\times\mathbf f\cdot\mathrm d\mathbf S
=\displaystyle\iint_{\mathcal S}\nabla\times\mathbf f\cdot\left(\dfrac{\partial\mathbf s}{\partial u}\times\dfrac{\partial\mathbf s}{\partial v}\right)\,\mathrm du\,\mathrm dv


where \mathbf s(u,v) is a vector-valued function that parameterizes \mathcal S. In this case, we can take

\mathbf s(u,v)=(u\cos v,u\sin v,2u^2\cos v\sin v)=(u\cos v,u\sin v,u^2\sin2v)

with 0\le u\le1 and 0\le v\le2\pi. Then

\mathrm d\mathbf S=\left(\dfrac{\partial\mathbf s}{\partial u}\times\dfrac{\partial\mathbf s}{\partial v}\right)\,\mathrm du\,\mathrm dv=(2u^2\cos v,2u^2\sin v,-u)\,\mathrm du\,\mathrm dv

and the integral becomes

\displaystyle\iint_{\mathcal S}(-2u^2\sin2v,-3u^2\cos^2v,-1)\cdot(2u^2\cos v,2u^2\sin v,-u)\,\mathrm du\,\mathrm dv
=\displaystyle\int_{v=0}^{v=2\pi}\int_{u=0}^{u=1}u-6u^4\sin^3v-4u^4\cos v\sin2v\,\mathrm du\,\mathrm dv=\pi<span />
4 0
2 years ago
What is the probability of rolling a 1 on a number cube And then a 4?​
mr Goodwill [35]
For each number,there is a 16 probability of rolling it (so 16 for the 1 and also 16 for the 4)
5 0
2 years ago
Explain the equation used to solve for the axis of symmetry.
sertanlavr [38]

Answer:

What the first person said

6 0
3 years ago
-6-5[-4-(6+12)]+(-5)
Luden [163]

Answer:

99

Step-by-step explanation:

-6-5[-4-(6+12)]+(-5)

Following PEMDAS

We work the parentheses from the inside out

-6-5[-4-(18)]+(-5)

-6-5[-22]+(-5)

Now we multiply

-6+110 -5

Now we add and subtract from left to right

104 -5

99

6 0
3 years ago
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