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lianna [129]
3 years ago
10

A transformation is a of a figure to the or​

Mathematics
1 answer:
Alex17521 [72]3 years ago
8 0

Answer: change, position, shape

Step-by-step explanation:

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What is the solution to the equation **<br> **2<br> X-8
Setler79 [48]

Answer. 2(x-4)

Step-by-step explanation:

common factor

2x-8

2(x-4)

6 0
3 years ago
Test designed to measure a student level of knowledge in basic area such as math science
PilotLPTM [1.2K]

Answer:

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Step-by-step explanation:

6 0
3 years ago
Finding the missing angles 35° and 145°
padilas [110]

Answer:

<h2>145°</h2>

Step-by-step explanation:

There are two ways to find the value of X

x + 35 = 180 ( sum of co-interior angles)

Move constant to R.H.S and change its sign

x = 180 - 35

Calculate the difference

x = 145°

You can use another way too.

x = 145° ( being vertically opposite angles)

Vertically opposite angles are always equal.

Hope this helps...

Best regards!!

5 0
3 years ago
Read 2 more answers
How many MLB teams lost money (had a negative "Operating Income") in 2016?
gavmur [86]
Detroit Tigers (-$36.4 million) <span>Dodgers (-$20.5 million), Miami Marlins (-$2.2 million), Baltimore Orioles (-$2.1 million)Kansas City Royals (-$0.9 million) </span>
3 0
3 years ago
Percentage grade averages were taken across all disciplines at a particular university, and the mean average was found to be 83.
Georgia [21]
Correct Ans:
Option A. 0.0100

Solution:
We are to find the probability that the class average for 10 selected classes is greater than 90. This involves the utilization of standard normal distribution.

First step will be to convert the given score into z score for given mean, standard deviation and sample size and then use that z score to find the said probability. So converting the value to z score:

z-score= \frac{90-83.6}{ \frac{8.7}{ \sqrt{10} } } \\  \\ &#10;z-score =2.326

So, 90 converted to  z score for given data is 2.326. Now using the z-table we are to find the probability of z score to be greater than 2.326. The probability comes out to be 0.01.

Therefore, there is a 0.01 probability of the class average to be greater than 90 for the 10 classes.
5 0
4 years ago
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