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1 year ago

Solve the inequality. -2c-7-9 Enter the correct answer

Mathematics

2 answers:

garik1379 [7]1 year ago

4 0

Answer:

-2c-16

Step-by-step explanation:

do 7-9 because it's the only thing you can solve.
--> -2c-16

jonny [76]1 year ago

3 0

C = 8

like terms first : -7-9 = -16
-2c-16
then you divide : -2/2 and -16/-2
c = 8

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Maria plans to double the amount of time she spends walking per day each week.she starts , on week 1 , walking 5 minutes per day

alisha [4.7K]

Answer:

a) 160 minutes per day

b) Find the graph attached

c) on 10th week Maria would be walking 2560 minutes per day

Step-by-step explanation:

Week 1 - 5 minutes per day

Week 2 - 10 minutes per day

Week 3 - 20 minutes per day

Week 4 - 40 minutes per day

Week 5 - 80 minutes per day

Week 6 - 160 minutes per day

a) 160 minutes per day

b) Find the graph attached

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2 years ago

Find the surface area of the tool box. Round your answer to the nearest tenth and explain your answer. Pls I NEED THE ANSWER NO

Andrej [43]

Answer:

807.8 in^2

Step-by-step explanation:

The total area of the box is the sum of the areas of all faces of the box. The top, bottom, front, and back faces are rectangles 18 in long. The end faces each consist of a rectangle and a triangle. We can compute the sum of these like this:

The areas of top, bottom, front, and back add up to be 18 inches wide by the length that is the perimeter of the end: 2·5in +2·8 in + 9.6 in = 35.8 in. That lateral area is ...

(18 in)(35.6 in) = 640.8 in^2

The area of the triangle on each end is equivalent to the area of a rectangle half as high, so we can compute the area of each end as ...

(9.6 in)(8.7 in) = 83.52 in^2

Then the total area is the lateral area plus the area of the two ends:

640.8 in^2 + 2·83.52 in^2 = 807.84 in^2 ≈ 807.8 in^2

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2 years ago

The combined weight of three basset hounds is 185 pounds. The two smaller dogs weigh the same. The difference between the larger

olga2289 [7]

Answer:

75 pounds

Step-by-step explanation:

(x) + (x) + (x+20) = 185

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3 years ago

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frosja888 [35]

Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

*Asymptotes*<br> g(x) =2x+1/x-3 <br><br> Give the domain and x and y intercepts

Nataly [62]

Answer: Assuming the function is $g(x)=\frac{2x+1}{x-3}$ :

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The horizontal asymptote is $y=2$ .

The vertical asymptote is $x=3$ .

Step-by-step explanation:

I'm going to assume the function is: $g(x)=\frac{2x+1}{x-3}$ and not $g(x)=2x+\frac{1}{x}-3$ .

So we are looking at $g(x)=\frac{2x+1}{x-3}$ .

The x-intercept is when y is 0 (when g(x) is 0).

Replace g(x) with 0.

$0=\frac{2x+1}{x-3}$

A fraction is only 0 when it's numerator is 0. You are really just solving:

$0=2x+1$

Subtract 1 on both sides:

$-1=2x$

Divide both sides by 2:

$\frac{-1}{2}=x$

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is when x is 0.

Replace x with 0.

$g(0)=\frac{2(0)+1}{0-3}$

$y=\frac{2(0)+1}{0-3}$

$y=\frac{0+1}{-3}$

$y=\frac{1}{-3}$

$y=-\frac{1}{3}$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The vertical asymptote is when the denominator is 0 without making the top 0 also.

So the deliminator is 0 when x-3=0.

Solve x-3=0.

Add 3 on both sides:

x=3

Plugging 3 into the top gives 2(3)+1=6+1=7.

So we have a vertical asymptote at x=3.

Now let's look at the horizontal asymptote.

I could tell you if the degrees match that the horizontal asymptote is just the leading coefficient of the top over the leading coefficient of the bottom which means are horizontal asymptote is $y=\frac{2}{1}$ . After simplifying you could just say the horizontal asymptote is $y=2$ .

Or!

I could do some division to make it more clear. The way I'm going to do this certain division is rewriting the top in terms of (x-3).

$y=\frac{2x+1}{x-3}=\frac{2(x-3)+7}{x-3}=\frac{2(x-3)}{x-3}+\frac{7}{x-3}$

$y=2+\frac{7}{x-3}$

So you can think it like this what value will y never be here.

7/(x-3) will never be 0 because 7 will never be 0.

So y will never be 2+0=2.

The horizontal asymptote is y=2.

(Disclaimer: There are some functions that will cross over their horizontal asymptote early on.)

6 0

3 years ago