All categories

2 years ago

Is the bisector of ∠ABC and is the bisector of ∠ACB. Also,

Mathematics

1 answer:

drek231 [11]2 years ago

8 0

Answer: No, it is not the bisector of angle ACB

Angle ABC has the vertex at point B. The middle point determines the vertex. This is why angle ABC is the exact same as angle CBA. Each time, B is in the middle.

However, angle ACB has point C in the middle so we're talking about a completely different angle. This is not a bisector because the line doesn't even go through point C at all. The line would need to curve, but bisectors must be straight lines.

You might be interested in

The exchange rate is : £1 = $1.54 how many £ would you get for $77

harina [27]

77 / 1.54 = <span>£ </span>53.8461538

Check = 53.85 x 1.54 = 77

3 0

3 years ago

Given these two data sets, IQ-GPA and IQ-SAT, how would you predict Justin’s SAT score based on his GPA? Explain.

daser333 [38]

Answer:

First, use the equation of the trend line to find the IQ that is expected by the GPA. Next, use the other equation of the trend line to find the SAT that is predicted by the IQ.

Step-by-step explanation:

have a great day!

8 0

2 years ago

Read 2 more answers

Find the equation of the straight line passing through the point (3,5)

marysya [2.9K]

Answer:

Step-by-step explanation:

y = 3x + 2

Slope m = 3

slope of the line perpendicular to this line = -3

Point (3,5)

y- y1 = m(x-x1)

y - 5 = -3(x-3)

y - 5 = -3*x-3 * -3

y - 5 = -3x + 9

y = -3x + 9 +5

y = -3x + 14

6 0

3 years ago

Three-fifths of a number increased by ten

Sav [38]

Answer: $\frac{3}{5} x+10$

Step-by-step explanation:

three-fifths of a number means multiply three-fifths by a variable $\frac{3}{5} x$

increased by 10 means addition +10

together it is $\frac{3}{5}x +10$

4 0

2 years ago

0/1 For positive integer n, n? = n! · (n − 1)! · … · 1! And n# = n? · (n − 1)? · … · 1?. What is the value of 4# · 3# · 2# · 1#?

MakcuM [25]

Answer:

331776

Step-by-step explanation:

Since n? = n! · (n − 1)! · … · 1! And n# = n? · (n − 1)? · … · 1?

Then 4# = 4? · (4 − 1)? · (4 − 2)?· 1?

= 4? · 3? · 2?· 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 4? = 4! · (4 − 1)! · (4 − 2)! · 1! = 4! · 3! · 2! · 1! = 288

Thus, 3? = 3! · (3 − 1)! · 1! = 3! · 2! · 1! = 12

Also, 2? = 2! · (2 − 1)! · 1! = 2! · 1! · 1! = 2

and 1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

So, 4# = 4? · 3? · 2?· 1? = 288 × 12 × 2 × 1 = 6912

We now find 3#

3# = 3? · (3 − 1)? · 1? = 3? · 2?· 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 3? = 3! · (3 − 1)! · 1! = 3! · 2! · 1! = 12

Thus, 2? = 2! · (2 − 1)! · 1! = 2! · 1! · 1! = 2

and, 1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

So, 3# = 3? · 2?· 1? = 12 × 2 × 1 = 24

We now find 2#

2# = 2? · (2 − 1)? · 1? = 2? · 1?· 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 2? = 2! · (2 − 1)! · 1! = 2! · 1! · 1! = 2

1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

So, 2# = 2?· 1? = 2 × 1 = 2

We now find 1#

1# = 1? · 1? = 1? · 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

And, 1# = 1? · 1? = 1 × 1 = 1

So, 4# · 3# · 2# · 1#? = 6912 · 24 · 2 · 1? = 331776

7 0

2 years ago