He first two are relatively easy. f(x-2) shifts it sideways (2 to the right in this case) f(x) -2 shifts it straight down (by 2)
f(2x) means replace x with 2x in the original 4(2x + 1)^2 − 3 if you factor out the 2 from the square root you get 4*sqr(2) ( x + ½)^2 - 3 which is now in the form a ( x -h)^2 + k the vertex is now at (-½, -3) (it used to be at (-1,-3) the "a" has gotten bigger, which makes the parabola "skinnier" (it goes up faster)
2•f(x) becomes 2*( 4(x + 1)2 − 3 ) = 8 (x+1)^2 -6 where is the vertex now? is this parabola fatter or skinnier than the original f(x) ?
Answer:
As you must know, If one root of the polynomial 7-√5, the other will be 7+√5 i.e irrational root occur in pairs.
A polynomial function cannot have single unreal i.e irrational root. It always occur in pairs.
So , consider a polynomial function of any degree, if it has a root 7-√5, then it must have another root as 7+√5.
A polynomial can't have 7-√5 as a single root.
Answer:
6 in.
Step-by-step explanation:
Rectangular prism
V = lwh l = 8 W = 3 h = 9
= 8(3)(9)
= 216
Cube
where s = length of side
216 = 
![s = \sqrt[3]{216}](https://tex.z-dn.net/?f=s%20%3D%20%5Csqrt%5B3%5D%7B216%7D)
= 6
Answer:
x=5
Step-by-step explanation:
That is your answer .
First you do 4x-3+3=2x+7+3
then,4x=2x+10,then
subtract 2x from both side
4x-2x=2x+10-2x
simplify
2x=10
divide both sides by 2 2x/2=10/2
simplfy and you get x=5
Hope this helps :)
