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ANEK [815]
4 years ago
14

John has been hired to design an exciting carnival ride. Tiff, the carnival owner, has decided to create the world's greatest fe

rris wheel. Tiff isn't into math; she simply has a vision and has told John these constraints on her dream: (i) the wheel should rotate counterclockwise with an angular speed of a = 15 RPM; (ii) the linear speed of a rider should be 200 mph; (iii) the lowest point on the ride should be c = 3 feet above the level ground.
Physics
1 answer:
tamaranim1 [39]4 years ago
7 0

Answer:

a) R = 186.742 ft

b) θ = 0.7854 rads

c) θ = 14.14 rads

Explanation:

Given:

- The linear tangential velocity v = 200 mph

- The angular frequency a = 15 RPM

- The distance of bottom point from ground c = 3 ft

Find:

- The radius R of the ferris wheel

-Once the wheel is built, John suggests that Tiff should take the first ride. The wheel starts turning when Tiff is  at the location P, which makes an angle θ with the horizontal, as pictured. It takes her 1.5 seconds to reach the  top of the ride. Find the angle θ. (Round your answer to two decimal places.)

-  Poor engineering causes Tiff's seat to fly off in 9 seconds. Describe where Tiff is located (an angle description)  the instant she becomes a human missile. (Give your answer as an angle measured counterclockwise from her starting point P.)

Solution:

- The relationship between linear v and rotational speed w is given by:

                                    v = R*w

                                    200*5280 / 60 = R*15*2*π

                                    R = 200*5280 / 60*15*2*π

                                    R = 186.742 ft

- the angle swept from point P to angle θ above horizontal is given in terms of angular speed:

                                    π/2 + θ = a*2π*1.5 / 60

                                    θ = 15*2π*1.5 / 60 - π/2

                                    θ = 0.7854 rads

- Similarly calculate the angle θ swept entirely till 9 seconds

                                    θ = a*2π*9 / 60

                                    θ = 15*2π*9 / 60

                                    θ = 14.14 rads

- The total angle swept from initial position is θ = 14.14.

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