Question

A 4.0 Ω resistor, an 8.0 Ω resistor, and a 12.0 Ω resistor are connected in parallel across a 24.0 V battery. What is the equivalent resistance of the circuit? Answer in units of Ω.
What is the current in the 4.0 Ω resistor? Answer in units of A.
What is the current in the 8.0 Ω resistor? Answer in units of A.

Answer 1

Answer:

The Equivalent resistance is 2.17 Ohms

The current in 4 ohm resistor is 6 amps

The current in 4 ohm resistor is 3 amps

Explanation:

Part 1

Equivalent resistance in parallel is given as

1/Re = 1/R1 + 1/R2  + 1/R3

By putting the values

1/Re = 1/4 + 1/8 + 1/12

Equivalent Resistance = 2.17 ohm

Part 2

By Using Ohm Law

V = IR

I = V/R

I = 24/4

I = 6 amp

Part 3

According to Ohms law

V = IR

I = V/R

I = 24/ 8

I = 3 amp

Answer 2

PART A)

Equivalent resistance in parallel is given as

$\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}$

now we have

$\frac{1}{R} = \frac{1}{4} + \frac{1}{8} + \frac{1}{12}$

$R = 2.18 ohm$

PART B)

since potential difference across all resistance will remain same as all are in parallel

so here we can use ohm's law

$V = iR$

for 4 ohm resistance we have

$24 = 4(i)$

$i = 6 A$

PART C)

since potential difference across all resistance will remain same as all are in parallel

so here we can use ohm's law

$V = iR$

for 8 ohm resistance we have

$24 = 8(i)$

$i = 3 A$