All categories

3 years ago

What times what =13?

Mathematics

2 answers:

patriot [66]3 years ago

8 0

Answer:

1x13 :-)

1 x 13 = 13

JulsSmile [24]3 years ago

5 0

6.5 x 2 = 13, because 6 x 2 = 12, and .5 x 2 = 1, and 12 + 1 = 13.

You might be interested in

LaTeX: \sqrt[]{36} 36 2) LaTeX: \sqrt[3]{-8} − 8 3 3) LaTeX: -\sqrt[]{100} − 100 4) LaTeX: \sqrt[3]{27} I'm sorry that's the bes

Mamont248 [21]

Given:

Consider the expression are

1) $\sqrt{36}$

2) $\sqrt[3]{-8}$

3) $-\sqrt{100}$

4) $\sqrt[3]{27}$

To find:

The simplified form of each expression.

Solution:

1. We have,

$\sqrt{36}=\sqrt{6^2}$

$\sqrt{36}=6$

Therefore, the value of this expression is 6.

2. We have,

$\sqrt[3]{-8}=(-8)^{\frac{1}{3}}$

$\sqrt[3]{-8}=((-2)^3)^{\frac{1}{3}}$

$\sqrt[3]{-8}=(-2)^{\frac{3}{3}}$

$\sqrt[3]{-8}=-2$

Therefore, the value of this expression is -2.

3. We have,

$-\sqrt{100}=-\sqrt{10^2}$

$-\sqrt{100}=-10$

Therefore, the value of this expression is -10.

4. We have,

$\sqrt[3]{27}=(27)^{\frac{1}{3}}$

$\sqrt[3]{27}=(3^3)^{\frac{1}{3}}$

$\sqrt[3]{27}=(3)^{\frac{3}{3}}$

$\sqrt[3]{27}=3$

Therefore, the value of this expression is 3.

3 0

3 years ago

Use Lagrange multipliers to find the maximum and minimum values of the function subject to the given constraint. (If an answer d

andrey2020 [161]

Answer:

The maximum value is 1/27 and the minimum value is 0.

Step-by-step explanation:

Note that the given function is equal to $(xyz)^2$ then it means that it is positive i.e $f(x,y,z)\geq 0$ .

Consider the function $F(x,y,z,\lambda)=x^2y^2z^2-\lambda (x^2+y^2+z^2-1)$

We want that the gradient of this function is equal to zero. That is (the calculations in between are omitted)

$\frac{\partial F}{\partial x} = 2x(y^2z^2 - \lambda)=0$

$\frac{\partial F}{\partial y} = 2y(x^2z^2 - \lambda)=0$

$\frac{\partial F}{\partial z} = 2z(x^2y^2 - \lambda)=0$

$\frac{\partial F}{\partial \lambda} = (x^2+y^2+z^2-1)=0$

Note that the last equation is our restriction. The restriction guarantees us that at least one of the variables is non-zero. We've got 3 options, either 1, 2 or none of them are zero.

If any of them is zero, we have that the value of the original function is 0. We just need to check that there exists a value for lambda.

Suppose that x is zero. Then, from the second and third equation we have that

$-2y\lambda = -2z\lambda$ . If lambda is not zero, then y =z. But, since $-2y\lambda=0$ and lambda is not zero, this implies that x=y=z=0 which is not possible. This proofs that if one of the variables is 0, then lambda is zero. So, having one or two variables equal to zero are feasible solutions for the problem.

Suppose that only x is zero, then we have the solution set $y^2+z^2=1$ .

If both x,y are zero, then we have the solution set $z^2=1$ . We can find the different solution sets by choosing the variables that are set to zero.

NOw, suppose that none of the variables are zero.

From the first and second equation we have that

$\lambda = y^2z^2 = x^2z^2$ which implies $x^2=y^2$

Also, from the first and third equation we have that

$\lambda = y^2z^2 = x^2y^2$ which implies $x^2=z^2$

So, in this case, replacing this in the restriction we have $3z^2=1$ , which gives as another solution set. On this set, we have $x^2=y^2=z^2=\frac{1}{3}$ . Over this solution set, we have that the value of our function is $\frac{1}{3^3}= \frac{1}{27}$

4 0

3 years ago

How do you solve 5+y=7

ss7ja [257]

In order to solve 5 + y = 7 you have to find the value of (y). In this case you could reverse do problem and do 7 - 5 to get the value of y. 7 - 5 = 2, which means y is equal to 2.

6 0

2 years ago

Read 2 more answers

The quadrilateral is a parallelogram. Find the measure of angles 1, 2 and 3

Vlad1618 [11]

Answer:

im pretty sure every angle is 80 degrees

Step-by-step explanation:

this is my first day in brainly, so im soo sorry if im wrong

4 0

3 years ago

Consider the quadratic function f(x)=2x^2-8x-10

Slav-nsk [51]

Answer:

f(x) = 2x² - 8x - 10.

This is a parabola open upward (since a>0) with an axis of symmetry = -b/2a:

a) axis of symmetry: x = -(-8)/(2*2) = 8/4 = 2. Then x = 2, which is the x component of the vertex

b) for x = 2, f(x) = f(2) = - 18 (component of y of the vertex)

c) VERTEX(2, - 18)

d) DISCRIMINENT: b² - 4.a.c = 64 - 4*2*(-10) = 144

Hope this helps! :)

6 0

3 years ago