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Vikentia [17]
3 years ago
13

What is the equation of the line with an X intercept of negative 2 and Y intercept of one

Mathematics
1 answer:
forsale [732]3 years ago
8 0

Answer:

y = 1/2x + 1

Step-by-step explanation:

Step 1: Find slope

(1-0)/(0+2) = 1/2

Step 2: Write equation

y = 1/2x + 1

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The sum of a number, n, and a number 5 larger than it is 41.
lina2011 [118]

Answer:

36

Step-by-step explanation:

If you set the equation up, it would be n + 5 = 41. If you subtract the 5 from both sides to get n by itself, you get n = 36.

8 0
3 years ago
14570.7 to 3 significant figures​
NemiM [27]

Answer:

what

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Linear or nonlinear​
Wittaler [7]

Answer:

Linear

Step-by-step explanation:

It increases by a steady rate, so it is linear.

5 0
3 years ago
You are planning to email to two lists. the first list has 1,200 names. the second list has 900 names. there are 150 names that
Snezhnost [94]

Answer:  There are 1800 unique names from both the lists.

Explanation:

Since we have given that

there are two lists :

In First list, number of names = 1200

In Second list, number of names = 900

According to question , we have also given that

there are 150 names that appear on both lists,

So,

Number of unique names in the first list  is given by

1200-150=1050

Number of unique names in the second list is given by

900-150=750

Therefore, total number of unique names is given by

1050+750=1800

Hence, there are 1800 unique names from both the lists.

3 0
3 years ago
Read 2 more answers
X = ? y = ? 16 45 degrees
mezya [45]

Let's put more details in the figure to better understand the problem:

Let's first recall the three main trigonometric functions:

\text{ Sine }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Hypotenuse}}\text{ Cosine }\theta\text{ = }\frac{\text{ Adjacent Side}}{\text{ Hypotenuse}}\text{ Tangent }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Adjacent Side}}

For x, we will be using the Cosine Function:

\text{ Cosine }\theta\text{ = }\frac{\text{ Adjacent Side}}{\text{ Hypotenuse}}Cosine(45^{\circ})\text{ = }\frac{\text{ x}}{\text{ 1}6}(16)Cosine(45^{\circ})\text{ =  x}(16)(\frac{1}{\sqrt[]{2}})\text{ = x}\text{ }\frac{16}{\sqrt[]{2}}\text{ x }\frac{\sqrt[]{2}}{\sqrt[]{2}}\text{ = }\frac{16\sqrt[]{2}}{2}\text{ 8}\sqrt[]{2}\text{ = x}

Therefore, x = 8√2.

For y, we will be using the Sine Function.

\text{  Sine }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Hypotenuse}}\text{ Sine }(45^{\circ})\text{ = }\frac{\text{ y}}{\text{ 1}6}\text{ (16)Sine }(45^{\circ})\text{ =  y}\text{ (16)(}\frac{1}{\sqrt[]{2}})\text{ = y}\text{ }\frac{16}{\sqrt[]{2}}\text{ x }\frac{\sqrt[]{2}}{\sqrt[]{2}}\text{ = }\frac{16\sqrt[]{2}}{2}\text{ 8}\sqrt[]{2}\text{ = y}

Therefore, y = 8√2.

5 0
1 year ago
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