this can be solve using newtons heating of cooling
(Ts – T) =(Ts – To)*e^(-kt)
Where Ts is the ambient temperature
To is initial temperature
T is the temperature at time t
t is the time
k is constant
fisrt solve the constant k for the given first scenario
(99 – 36) = (99 – 46)*e(-5k)
K = -0.0346
Using k, solve T at t = 13 min
(99 – 46) = (99 – T)*e(-13*(-0.0346)
T = 58.82 degree F
Answer:
The zeros are (-5,0) and (4,0)
Step-by-step explanation:
Ratio: 3/4 : 1/2
We can also write this as:
3/4 / 1/2
Flip the 2nd fraction and multiply:
3/4 * 2/1
Multiply the numerators and denominators together:
6/4
Simplify:
3/2
78 / 0.26 = 300 so the answer is 300
32. Answer: 2+5×3=17
33. Answer: 2×5+3=17
34. Answer: 2×5×3=30
35. Answer: 2×5-3=7
