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2 years ago

How to do parcial-quotients algorithm

Mathematics

1 answer:

tiny-mole [99]2 years ago

6 0

Well first try your best then I will help u later don't always give up be strong

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Please help meeeeeeeeee

castortr0y [4]

Answer:

37.3% is the take off

Step-by-step explanation:

so an easy route is to subtract the price after the reduction

89.99-56.49= 33.5 that is 37.3 percent

because 62.78% of 89.99 is 56.486723 round i and you get 56.49 so this is a check your work

4 0

3 years ago

Suppose that W1, W2, and W3 are independent uniform random variables with the following distributions: Wi ~ Uni(0,10*i). What is

nadya68 [22]

I'll leave the computation via R to you. The $W_i$ are distributed uniformly on the intervals $[0,10i]$ , so that

$f_{W_i}(w)=\begin{cases}\dfrac1{10i}&\text{for }0\le w\le10i\\\\0&\text{otherwise}\end{cases}$

each with mean/expectation

$E[W_i]=\displaystyle\int_{-\infty}^\infty wf_{W_i}(w)\,\mathrm dw=\int_0^{10i}\frac w{10i}\,\mathrm dw=5i$

and variance

$\mathrm{Var}[W_i]=E[(W_i-E[W_i])^2]=E[{W_i}^2]-E[W_i]^2$

We have

$E[{W_i}^2]=\displaystyle\int_{-\infty}^\infty w^2f_{W_i}(w)\,\mathrm dw=\int_0^{10i}\frac{w^2}{10i}\,\mathrm dw=\frac{100i^2}3$

so that

$\mathrm{Var}[W_i]=\dfrac{25i^2}3$

Now,

$E[W_1+W_2+W_3]=E[W_1]+E[W_2]+E[W_3]=5+10+15=30$

and

$\mathrm{Var}[W_1+W_2+W_3]=E\left[\big((W_1+W_2+W_3)-E[W_1+W_2+W_3]\big)^2\right]$

$\mathrm{Var}[W_1+W_2+W_3]=E[(W_1+W_2+W_3)^2]-E[W_1+W_2+W_3]^2$

We have

$(W_1+W_2+W_3)^2={W_1}^2+{W_2}^2+{W_3}^2+2(W_1W_2+W_1W_3+W_2W_3)$

$E[(W_1+W_2+W_3)^2]$

$=E[{W_1}^2]+E[{W_2}^2]+E[{W_3}^2]+2(E[W_1]E[W_2]+E[W_1]E[W_3]+E[W_2]E[W_3])$

because $W_i$ and $W_j$ are independent when $i\neq j$ , and so

$E[(W_1+W_2+W_3)^2]=\dfrac{100}3+\dfrac{400}3+300+2(50+75+150)=\dfrac{3050}3$

giving a variance of

$\mathrm{Var}[W_1+W_2+W_3]=\dfrac{3050}3-30^2=\dfrac{350}3$

and so the standard deviation is $\sqrt{\dfrac{350}3}\approx\boxed{116.67}$

# # #

A faster way, assuming you know the variance of a linear combination of independent random variables, is to compute

$\mathrm{Var}[W_1+W_2+W_3]$

$=\mathrm{Var}[W_1]+\mathrm{Var}[W_2]+\mathrm{Var}[W_3]+2(\mathrm{Cov}[W_1,W_2]+\mathrm{Cov}[W_1,W_3]+\mathrm{Cov}[W_2,W_3])$

and since the $W_i$ are independent, each covariance is 0. Then

$\mathrm{Var}[W_1+W_2+W_3]=\mathrm{Var}[W_1]+\mathrm{Var}[W_2]+\mathrm{Var}[W_3]$

$\mathrm{Var}[W_1+W_2+W_3]=\dfrac{25}3+\dfrac{100}3+75=\dfrac{350}3$

and take the square root to get the standard deviation.

8 0

2 years ago

Madeline sold 200 tickets for a charter flight to Dallas. Some paid $200 for their tickets and some paid

4vir4ik [10]

Answer:

Let x = number of regular tickets sold.

Let y represent the number of student tickets sold.

12x+8y≤100012x+8y≤1000

x+y≥200x+y≥200

12x+8y≤20012x+8y≤200

x+y≤200x+y≤200

12x+8y≥1000

hope this helps

Step-by-step explanation:

8 0

2 years ago

SCORPION-xisa [38]

Answer:

It's 15

i took the test

Step-by-step explanation:

5 0

2 years ago

Write the equation of the line that has a y-value that increases by 4 for every x that increases by 1. It also crosses the y-axi

34kurt

Slope = rise/run. the rise is the increase of y and the run is the increase of x. that would make it 4/1 or just 4. now that you have the slope, plug everything into slope-intercept form. y = mx + b. m = the slope. b = the y-intercept. once every thing is plugged in, then the equation would be y = 4x - 2.
i hope i helped

6 0

2 years ago