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Irina-Kira [14]
2 years ago
7

How to do parcial-quotients algorithm

Mathematics
1 answer:
tiny-mole [99]2 years ago
6 0
Well first try your best then I will help u later don't always give up be strong
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Please help meeeeeeeeee ​
castortr0y [4]

Answer:

37.3% is the take off

Step-by-step explanation:

so an easy route is to subtract the price after the reduction

89.99-56.49= 33.5 that is 37.3 percent

because 62.78% of 89.99 is 56.486723 round i and you get 56.49 so this is a check your work

4 0
3 years ago
Suppose that W1, W2, and W3 are independent uniform random variables with the following distributions: Wi ~ Uni(0,10*i). What is
nadya68 [22]

I'll leave the computation via R to you. The W_i are distributed uniformly on the intervals [0,10i], so that

f_{W_i}(w)=\begin{cases}\dfrac1{10i}&\text{for }0\le w\le10i\\\\0&\text{otherwise}\end{cases}

each with mean/expectation

E[W_i]=\displaystyle\int_{-\infty}^\infty wf_{W_i}(w)\,\mathrm dw=\int_0^{10i}\frac w{10i}\,\mathrm dw=5i

and variance

\mathrm{Var}[W_i]=E[(W_i-E[W_i])^2]=E[{W_i}^2]-E[W_i]^2

We have

E[{W_i}^2]=\displaystyle\int_{-\infty}^\infty w^2f_{W_i}(w)\,\mathrm dw=\int_0^{10i}\frac{w^2}{10i}\,\mathrm dw=\frac{100i^2}3

so that

\mathrm{Var}[W_i]=\dfrac{25i^2}3

Now,

E[W_1+W_2+W_3]=E[W_1]+E[W_2]+E[W_3]=5+10+15=30

and

\mathrm{Var}[W_1+W_2+W_3]=E\left[\big((W_1+W_2+W_3)-E[W_1+W_2+W_3]\big)^2\right]

\mathrm{Var}[W_1+W_2+W_3]=E[(W_1+W_2+W_3)^2]-E[W_1+W_2+W_3]^2

We have

(W_1+W_2+W_3)^2={W_1}^2+{W_2}^2+{W_3}^2+2(W_1W_2+W_1W_3+W_2W_3)

E[(W_1+W_2+W_3)^2]

=E[{W_1}^2]+E[{W_2}^2]+E[{W_3}^2]+2(E[W_1]E[W_2]+E[W_1]E[W_3]+E[W_2]E[W_3])

because W_i and W_j are independent when i\neq j, and so

E[(W_1+W_2+W_3)^2]=\dfrac{100}3+\dfrac{400}3+300+2(50+75+150)=\dfrac{3050}3

giving a variance of

\mathrm{Var}[W_1+W_2+W_3]=\dfrac{3050}3-30^2=\dfrac{350}3

and so the standard deviation is \sqrt{\dfrac{350}3}\approx\boxed{116.67}

# # #

A faster way, assuming you know the variance of a linear combination of independent random variables, is to compute

\mathrm{Var}[W_1+W_2+W_3]

=\mathrm{Var}[W_1]+\mathrm{Var}[W_2]+\mathrm{Var}[W_3]+2(\mathrm{Cov}[W_1,W_2]+\mathrm{Cov}[W_1,W_3]+\mathrm{Cov}[W_2,W_3])

and since the W_i are independent, each covariance is 0. Then

\mathrm{Var}[W_1+W_2+W_3]=\mathrm{Var}[W_1]+\mathrm{Var}[W_2]+\mathrm{Var}[W_3]

\mathrm{Var}[W_1+W_2+W_3]=\dfrac{25}3+\dfrac{100}3+75=\dfrac{350}3

and take the square root to get the standard deviation.

8 0
2 years ago
Madeline sold 200 tickets for a charter flight to Dallas. Some paid $200 for their tickets and some paid
4vir4ik [10]

Answer:

Let x = number of regular tickets sold.

Let y represent the number of student tickets sold.

12x+8y≤100012x+8y≤1000

x+y≥200x+y≥200

12x+8y≤20012x+8y≤200

x+y≤200x+y≤200

12x+8y≥1000

hope this helps

Step-by-step explanation:

8 0
2 years ago
ΔABC is similar to ΔDEF. The length of segment AC is 12 cm. The length of segment BC is 18 cm. The length of segment DF is 10 cm
SCORPION-xisa [38]

Answer:

It's 15

i took the test

Step-by-step explanation:

5 0
2 years ago
Write the equation of the line that has a y-value that increases by 4 for every x that increases by 1. It also crosses the y-axi
34kurt
Slope = rise/run.      the rise is the increase of y and the run is the increase of x. that would make it 4/1 or just 4. now that you have the slope, plug everything into slope-intercept form. y = mx + b. m = the slope. b = the y-intercept. once every thing is plugged in, then the equation would be y = 4x - 2.
i hope i helped
6 0
2 years ago
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