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3 years ago

Help, I need answer ASAP

Mathematics

1 answer:

Kryger [21]3 years ago

3 0

Step-by-step explanation:

HL states that a hypotenuse and leg of a right triangle must be congruent, so you would need to know the hypotenuses are congruent and a leg is congruent. For 6, You're only given 2 sides instead of 3, and since this is a Side-Side-Side Postulate, you must have the third sides be congruent. For 7, Angle-Side-Angle requires to known congruent angles and a side in between them, so you would need to know that angle I is congruent to angle L. Lastly, Side-Angle-Side needs two sides and an angle between them, so you would need to know that side JI is congruent to HD. HI is already congruent to itself by the Reflexive Property, so you only need to know JI ≅ HD.

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33. Suppose you were on a planet where the

tatyana61 [14]

Answer:

a) 3.675 m

b) 3.67m

Explanation:

We are given acceleration due to gravity on earth = $9.8ms^-2$

And on planet given = $2.0ms^-2$

A) Since the maximum jump height is given by the formula

$\mathrm{H}=\frac{\left(\mathrm{v} 0^{2} \times \sin 2 \emptyset\right)}{2 \mathrm{g}}$

Where H = max jump height,

v0 = velocity of jump,

Ø = angle of jump and

g = acceleration due to gravity

Considering velocity and angle in both cases

$\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 2}{\mathrm{g} 1}$

Where H1 = jump height on given planet,

H2 = jump height on earth = 0.75m (given)

g1 = 2.0 $ms^-2$ and

g2 = 9.8 $ms^-2$

Substituting these values we get H1 = 3.675m which is the required answer

B) Formula to find height of ball thrown is given by

$\mathrm{h}=(\mathrm{v} 0 * \mathrm{t})+\frac{\mathrm{a} *\left(t^{2}\right)}{2}$

which is due to projectile motion of ball

Now h = max height,

v0 = initial velocity = 0,

t = time of motion,

a = acceleration = g = acceleration due to gravity

Considering t = same on both places we can write

$\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 1}{\mathrm{g} 2}$

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations

substituting h2 = 18m, g1 = 2.0 $ms^-2$ and g2 = 9.8 $ms^-2$

We get h1 = 3.67m which is the required height

6 0

4 years ago

let y =2t+5 be a linear function representing the distance from home for an ant t minutes after starting out from a location nea

Akimi4 [234]

Answer: T=1/2 Y + -5/2

Step-by-step explanation:

y=2t+5

2t+5 +-5= y +-5

2t=y-5 2t/2=y-5/2

t=1/2y+-5/2

= t=1/2y + -5/2

7 0

3 years ago

Read 2 more answers

I’m really struggling with this. Any help is appreciated! Thank you

fgiga [73]

Answer:

<h2>the mean absolute deviation value is 5</h2>

7 0

4 years ago

Juan purchased an antique that had a value of \$200$200dollar sign, 200 at the time of purchase. Each year, the value of the ant

garri49 [273]

Answer:

<h2>The value of a is $(\frac{11}{10} )^{222}$ .</h2>

Step-by-step explanation:

At the time of purchase, the value of the antique is $200.

After one year the value will increase 10%.

Hence, after one year, the value of the antique will be $\frac{110}{100} \times200$ = 220.

Similarly, after two year, the value will be $200\times (\frac{110}{100} )^{2}$ .

Thus, 222 years after purchase, the value of the antique will be $200\times (\frac{110}{100} )^{222} = 200\times (\frac{11}{10} )^{222}$ .

5 0

4 years ago

A plane flew a total of 2,220 miles. Its average

mojhsa [17]

Answer:

4 Hours

Step-by-step explanation:

1). Since Speed (V) = Distance (D)/Time (t)

2). Then t=D/V ( transpose)

3). So t= 2220/555

t= 4 hours

The plane flew for four hours

8 0

4 years ago