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kolbaska11 [484]
3 years ago
6

Help!, i honestly forgot this lol

Mathematics
2 answers:
jeka943 years ago
8 0

Answer:

A

Step-by-step explanation:

nlexa [21]3 years ago
4 0

Answer:

C. 21 to 28

Step-by-step explanation:

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chelsea deposits $600 into a bank account and is earning simple interest.After 4 years her account has a balance of $621.60.If C
olga nikolaevna [1]
If she deposited $600 and had $621.60 after four years, then she earned: $621.60 - $600 = $21.60 in four years. It means in one year she earned $21.60 ÷ 4 = $5.40. Now we have to find out how many percent of $600 is $5.40:

$5.40 = x% from $600
5.4 = x/100 * 600
5.4 = 600x/100                 / * 100 (both sides)
540 = 600x                       / ÷ 600 (both sides)
x = 0.9

So the interest rate was 0.9% annually.

Now we have to find out how much is 0.9% from $1100:

$1100 * 0.9% =
= 1100 * 9/1009 =
= 9900/1000 =
= 9.9

It means in one year she would earn $9.90. After 7 years she would earn $9.90 * 7 = $69.30, so she would have in her account:

$1100 + $69.30 = <u>$1169.30</u>
8 0
3 years ago
What is the equation in point-slope form if a line that passes through points (3,-5) and (-8,4)?
nignag [31]

The slope-point formula:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

We have (3, -5) and (-8, 4).

Substitute:

m=\dfrac{4-(-5)}{-8-3}=\dfrac{9}{-11}=-\dfrac{9}{11}\\\\y-4=-\dfrac{9}{11}(x-(-8))\\\\y-4=-\dfrac{9}{11}(x+8)\to C)

3 0
3 years ago
Solve the systems of equations y=2x and y=-x - 6
slava [35]

Answer:

y = -4

x = -2

Step-by-step explanation:

Hi there...

y = 2x

y = -x - 6

Since why is equal to 2x, we can plug it in for y in the second equation. Here's what I mean...

2x = -x - 6

add x on both sides...

3x = -6

divide by 3 on both sides...

x = -2

Now, plug in x for y. Here's what I mean...

y = 2x

y = 2 (-2)

y = -4

Hope this helps :)

7 0
3 years ago
A farmer has sheep and cattle in the ratio 8:3. How many sheep has the farmer if he has 180 cattle?
ruslelena [56]
There are 480 Sheep.
3 0
3 years ago
Read 2 more answers
The indicated function y1(x is a solution of the given differential equation. use reduction of order or formula (5 in section 4.
Taya2010 [7]
Given a solution y_1(x)=\ln x, we can attempt to find a solution of the form y_2(x)=v(x)y_1(x). We have derivatives

y_2=v\ln x
{y_2}'=v'\ln x+\dfrac vx
{y_2}''=v''\ln x+\dfrac{v'}x+\dfrac{v'x-v}{x^2}=v''\ln x+\dfrac{2v'}x-\dfrac v{x^2}

Substituting into the ODE, we get

v''x\ln x+2v'-\dfrac vx+v'\ln x+\dfrac vx=0
v''x\ln x+(2+\ln x)v'=0

Setting w=v', we end up with the linear ODE

w'x\ln x+(2+\ln x)w=0

Multiplying both sides by \ln x, we have

w' x(\ln x)^2+(2\ln x+(\ln x)^2)w=0

and noting that

\dfrac{\mathrm d}{\mathrm dx}\left[x(\ln x)^2\right]=(\ln x)^2+\dfrac{2x\ln x}x=(\ln x)^2+2\ln x

we can write the ODE as

\dfrac{\mathrm d}{\mathrm dx}\left[wx(\ln x)^2\right]=0

Integrating both sides with respect to x, we get

wx(\ln x)^2=C_1
w=\dfrac{C_1}{x(\ln x)^2}

Now solve for v:

v'=\dfrac{C_1}{x(\ln x)^2}
v=-\dfrac{C_1}{\ln x}+C_2

So you have

y_2=v\ln x=-C_1+C_2\ln x

and given that y_1=\ln x, the second term in y_2 is already taken into account in the solution set, which means that y_2=1, i.e. any constant solution is in the solution set.
4 0
3 years ago
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