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alina1380 [7]
4 years ago
6

Gasoline, if 9.00 liters has a mass of 6120 g. Find the density in g/cm^3

Chemistry
1 answer:
Ilya [14]4 years ago
5 0

Answer:

The density of gasoline is 0.68 g/cm³.

Explanation:

Given data:

Volume of gasoline = 9.00 L

Mass of gasoline = 6120 g

Density of gasoline = ?

Solution:

first of all we will convert the unit, L to mL.

9.00 L × 1000 mL / 1 L = 9000 mL

Formula:

d = m/v

d = density

m = mass

v= volume

d = 6120 g/ 9000 mL

d = 0.68 g/cm³  ( mL =cm³ )

Thus, density of gasoline is 0.68 g/cm³  .

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GrogVix [38]
The formula for the self ionization of water is 2H₂O(l)⇄H₃O⁺(aq)+OH⁻(aq)

The hydronium (H₃O⁺) is usually just referred to as a hydrogen ion or a proton (H⁺) and hydroxide (OH⁻) doesn't have another name that I am aware of.  These ions do stay in solution.  However the concentrations are really small and the equilibrium constant (K(w)) is 1×10⁻¹⁴.

I hope this helps.  Let me know if anything is unclear.
5 0
3 years ago
Activity C: Hydrolysis of Carbohydrates As discussed earlier, disaccharides are composed of two monosaccharides linked together.
adelina 88 [10]

Answer:

Sucrose: glucose and fructose

Explanation:

<em>What monosaccharides will result from the hydrolysis of sucrose?</em>

<em>Sucrose</em> is a <em>disaccharide</em> composed of 2 different <em>monosaccharides</em>: glucose and fructose joining by a 1 ⇒ 2 bond. These monosaccharides will be released upon the hydrolysis of sucrose.

<em>What monosaccharide will result from the hydrolysis of starch?</em>

<em>Starch</em> is a <em>polysaccharide</em> composed of numerous glucose monomers joined by glycosidic bonds (1 ⇒ 4 and 1 ⇒ 6). These monosaccharides will be released upon the hydrolysis of starch.

4 0
4 years ago
A gas cylinder of volume 5.00 l contains 1.00 g of ar and 0.500 g of ne. the temperature is 275 k. find the partial pressure of
amid [387]
<span>11.3 kPa The ideal gas law is PV = nRT where P = Pressure V = Volume n = number of moles R = Ideal gas constant (8.3144598 L*kPa/(K*mol) ) T = Absolute temperature We have everything except moles and volume. But we can calculate moles by starting with the atomic weight of argon and neon. Atomic weight argon = 39.948 Atomic weight neon = 20.1797 Moles Ar = 1.00 g / 39.948 g/mol = 0.025032542 mol Moles Ne = 0.500 g / 20.1797 g/mol = 0.024777375 mol Total moles gas particles = 0.025032542 mol + 0.024777375 mol = 0.049809918 mol Now take the ideal gas equation and solve for P, then substitute known values and solve. PV = nRT P = nRT/V P = 0.049809918 mol * 8.3144598 L*kPa/(K*mol) * 275 K/5.00 L P = 113.8892033 L*kPa / 5.00 L P = 22.77784066 kPa Now let's determine the percent of pressure provided by neon by calculating the percentage of neon atoms. Divide the number of moles of neon by the total number of moles. 0.024777375 mol / 0.049809918 mol = 0.497438592 Now multiply by the pressure 0.497438592 * 22.77784066 kPa = 11.33057699 kPa Round the result to 3 significant figures, giving 11.3 kPa</span>
8 0
3 years ago
Equal amounts of N2 and O2 are added, under certain conditions, to a closed container. Which changes occur in the reverse reacti
geniusboy [140]
1) The forward reaction is N2 (g) + O2 (g)  → 2NO

(that reaction requires special contitions because at normal pressures and temperatures N2 and O2 do not react to form another compound.

2) The equiblibrium equation is

  N2 (g) + O2 (g)  ⇄ 2NO

3) Then, the reverse reaction is

2NO → N2(g) + O2(g)

Answer: 2NO → N2(g) + O2(g)
4 0
3 years ago
In physical change the make up of matter is changedWho or false
Harrizon [31]

Answer:

False

That is a chemical change

4 0
3 years ago
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