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Norma-Jean [14]
3 years ago
5

Give me two sources of air pollution ​

Chemistry
1 answer:
Liula [17]3 years ago
6 0

Answer:

Explanation:

Types of Sources

There are four main types of air pollution sources: mobile sources – such as cars, buses, planes, trucks, and trains. stationary sources – such as power plants, oil refineries, industrial facilities, and factories. area sources – such as agricultural areas, cities, and wood burning fireplaces.

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A 0.529-g sample of gas occupies 125 ml at 60. cm of hg and 25°c. what is the molar mass of the gas?
Llana [10]

<span>Let's </span>assume that the gas has ideal gas behavior. <span>
Then we can use ideal gas formula,
PV = nRT<span>

</span><span>Where, P is the pressure of the gas (Pa), V is the volume of the gas (m³), n is the number of moles of gas (mol), R is the universal gas constant ( 8.314 J mol</span></span>⁻¹ K⁻¹) and T is temperature in Kelvin.<span>
<span>
</span>P = 60 cm Hg = 79993.4 Pa
V = </span>125  mL = 125 x 10⁻⁶ m³

n = ?

<span> R = 8.314 J mol</span>⁻¹ K⁻¹<span>
T = 25 °C = 298 K
<span>
By substitution,
</span></span>79993.4 Pa<span> x </span>125 x 10⁻⁶ m³ = n x 8.314 J mol⁻¹ K⁻¹ x 298 K<span>
                                          n = 4.0359 x 10</span>⁻³ mol

<span>
Hence, moles of the gas</span> = 4.0359 x 10⁻³ mol<span>

Moles = mass / molar mass

</span>Mass of the gas  = 0.529 g 

<span>Molar mass of the gas</span> = mass / number of moles<span>
                                    = </span>0.529 g / 4.0359 x 10⁻³ mol<span>
<span>                                    = </span>131.07 g mol</span>⁻¹<span>

Hence, the molar mass of the given gas is </span>131.07 g mol⁻¹

4 0
3 years ago
Help in chem please!!!!!!
IgorLugansk [536]

This is a one-step unit analysis problem.  Since we are staying in moles, grams of our compound, and thus molar mass, is not needed.

1 mole is equal to 6.022x10²³ particles as given, so:

1.5x10^{24} particles FeO_{2} (\frac{1mol}{6.022x10^{23}particles } )=2.49 molFeO_{2}

<h3>Answer:</h3>

2.49 mol

Let me know if you have any questions.

3 0
3 years ago
A solution that contains a large amount of salt and a small amount of water is said to be a _______ solution. A. diffused B. uns
Pachacha [2.7K]

Answer:

D. Concentrated

Explanation:

5 0
3 years ago
Read 2 more answers
Measurements show that the enthalpy of a mixture of gaseous reactants decreases by 162. kJ during a certain chemical reaction, w
puteri [66]

Answer:

= -356KJ

<em>therefore, the reaction where heat is released is exothermic reaction since theΔH is negative</em>

Explanation:

given that enthalpy of gaseous reactants decreases by 162KJ and workdone is -194KJ

then,

change in enthalpy (ΔH) = -162( released energy)

work(w) = -194KJ

change in enthalpy is said to be negative if the heat is evolved during the reaction while heat change(ΔH) is said to be positive if the heat required for the reaction occurs.

At constant pressure the change in enthalpy is given as

ΔH = ΔU + PΔV

ΔU = change in energy

ΔV = change in volume

P = pressure

w =  -pΔV

therefore,

ΔH = ΔU -W

to evaluate  energy change we have,

ΔU =ΔH + W

ΔU = -162+ (-194KJ)

= -356KJ

<em>therefore, the reaction where heat is released is exothermic reaction since theΔH is negative</em>

6 0
3 years ago
BRAINLIEST PLEASE HELP!!
omeli [17]

Answer:gimme iT OR mama will cOMEEEEEEEEEEEEEEEEE have a nice day

Explanation:

6 0
3 years ago
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