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3 years ago

Give me two sources of air pollution

Chemistry

1 answer:

Liula [17]3 years ago

6 0

Answer:

Explanation:

Types of Sources

There are four main types of air pollution sources: mobile sources – such as cars, buses, planes, trucks, and trains. stationary sources – such as power plants, oil refineries, industrial facilities, and factories. area sources – such as agricultural areas, cities, and wood burning fireplaces.

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Water that is heated by the sun evaporates.

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Answer:

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Explanation:

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How many grams of the molecule (C2H4O2) would be required to make 1 L of a 0.5 M solution of the molecule? (Carbon = 12, Oxygen

NeTakaya

MC₂H₄O₂ = 2 * 12 g/mol + 4 * 1 g/mol + 2 * 16 g/mol = 60 g/mol

c = 0.5 mol/L

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answer E

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How many grams of molybdenum(Mo) are in 2.68E24 atoms of Mo?

loris [4]

<h3>Answer:</h3>

427 g Mo

<h3>General Formulas and Concepts:</h3>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table
Using Dimensional Analysis
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<h3>Explanation:</h3>

<u>Step 1: Define</u>

2.68E24 atoms Mo or 2.68 × 10²⁴ atoms Mo

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of Mo - 95.94 g/mol

<u>Step 3: Convert</u>

<u /> $2.68 \cdot 10^{24} \ atoms \ Mo(\frac{1 \ mol \ Mo}{6.022 \cdot 10^{23} \ atoms \ Mo} )(\frac{95.94 \ g \ Mo}{1 \ mol \ Mo} )$ = 426.966 g Mo

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

426.966 g Mo ≈ 427 g Mo

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eimsori [14]

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Give me two sources of air pollution ​

Give me two sources of air pollution