50 POINTS FOR THIS ALGEBRA WORD PROBLEM
2 answers:
Let x,x+2,x+4,x+6 be 4 consecutive no then,
sum of first 3 no=4x+12
According to condition,
20 less than 5 times 4th= 4 more than sum of 1st,2nd and 3rd
5(x+6)-20=4+(sum of first 3 no)
5(x+6)-20=4+(4x+12)
5(x+6)-20=4x+16
5x+30-20=4x+16
5x+10=4x+16
5x-4x=16-10
x=6
So,
1st no=x= 6
2nd no = x + 2 = 8
3r d no=x+ 4 = 6 + 4 = 1 0
4th no = x + 6 = 6 + 6 = 1 2
Answer:
Let x,x+2,x+4,x+6 be 4 consecutive no then,
sum of first 3 no=4x+12
According to condition,
20 less than 5 times 4th= 4 more than sum of 1st,2nd and 3rd
5(x+6)-20=4+(sum of first 3 no)
5(x+6)-20=4+(4x+12)
5(x+6)-20=4x+16
5x+30-20=4x+16
5x+10=4x+16
5x-4x=16-10
x=6
So,
1st no=x=6
2nd no=x+2=8
3rd no=x+4=6+4=10
4th no=x+6=6+6=12
Step-by-step explanation:
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