Question

50 POINTS FOR THIS ALGEBRA WORD PROBLEM

Answer 1

Let x,x+2,x+4,x+6 be 4 consecutive no then,

sum of first 3 no=4x+12

According to condition,

20 less than 5 times 4th= 4 more than sum of 1st,2nd and 3rd

5(x+6)-20=4+(sum of first 3 no)

5(x+6)-20=4+(4x+12)

5(x+6)-20=4x+16

5x+30-20=4x+16

5x+10=4x+16

5x-4x=16-10

x=6

So,

1st no=x=6

2nd no=x+2=8

3rd no=x+4=6+4=10

4th no=x+6=6+6=12

Answer 2

Answer:

Let x,x+2,x+4,x+6 be 4 consecutive no then,

sum of first 3 no=4x+12

According to condition,

20 less than 5 times 4th= 4 more than sum of 1st,2nd and 3rd

5(x+6)-20=4+(sum of first 3 no)

5(x+6)-20=4+(4x+12)

5(x+6)-20=4x+16

5x+30-20=4x+16

5x+10=4x+16

5x-4x=16-10

x=6

So,

1st no=x=6

2nd no=x+2=8

3rd no=x+4=6+4=10

4th no=x+6=6+6=12

Step-by-step explanation: