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german
2 years ago
11

A function f is defined by f(x) = 2x - 3. By writing the full working, write the values of (a) f(0) (b) f(-2) (c) f(3) (d) f(-1)

Mathematics
1 answer:
AlladinOne [14]2 years ago
6 0
A) f(x) = 2x - 3
f(0) = 2(0) - 3
f(0) = 0 - 3
f(0) = -3

b) f(x) = 2x - 3
f(-2) = 2(-2) - 3
f(-2) = -4 - 3
f(-2) = -7

c) f(x) = 2x - 3
f(3) = 2(3) - 3
f(3) = 6 - 3
f(3) = 3

d) f(x) = 2x - 3
f(-1) = 2(-1) - 3
f(-1) = -2 - 3
f(-1) = -5
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DedPeter [7]
Let's take these one at a time.
A
The A choice is that the y intercept of g(x) < y intercept of f(x). Remember, a y intercept occurs when x = 0
g(x) = 2 * sqrt(x) - 8
g(0) = 2*0 - 8
g(0) = - 8
=======
f(x) = - 4 when x = 0 (you just read it.) - 4 is greater than -8. That's a true statement. Think money. Would you rather be 4 dollars in debt or 8 dollars in debt? 
A: True <<<<<< answer for A.

B
y intercept  occurs when x = 0 The values of f(x) and g(x) have been found in part A.

Are they equal?

The y intercept of g(x) = g(0) = 2*sqrt(0) - 8 = - 8
The y intercept of f(x) = f(x)  = - 4 when x = 0 

Conclusion
They are not equal and B is not the answer.

C
The x intercept occurs when y = 0
g(x) = 0 
0 = 2*sqrt(x) - 8
8 = 2*sqrt(x)
4 = sqrt(x)
x = 16
======
When f(x) = 0, x = 16.

Conclusion
The x intercepts are both 16. This statement is true.
C: True <<<<<< answer.

D
If the condition is anything but equal, the statement is false. g(x) is not greater then f(x).

D <<<<<< False.
3 0
2 years ago
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