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3 years ago

¡Help me please! ¿. 2(8 + 2x) = 6x + 10 .?

Mathematics

1 answer:

Svetlanka [38]3 years ago

3 0

Answer:

x = 3

Step-by-step explanation:

2(8 + 2x) = 6x + 10

16 + 4x = 6x + 10

4x - 6x = 10 - 16

-2x = -6

x = -6/-2

x = 3

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What value of n makes the equation true -1/5+7=2

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Answer:

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Step-by-step explanation:

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3 years ago

Divide 36X cubed -96X squared +48X by 12 X

saul85 [17]

Answer:

The answer to your question is 3x³ - 8x + 4

Step-by-step explanation:

Divide 36³ - 96x² + 48x by 12x

3x³ - 8x + 4

12x 36x³ - 96x² + 48x

- 36x³

0 - 96x²

+ 96x²

0 + 48x

- 48x

1st step. Divide 36x³ by 12 x = 3x², place the result above 36x³

2nd step. Multiply 3x³ by 12x, change the sign and place the result below 36x³.

3rd step. Add and place -96x² next to the result

4rd step. Divide -96x² by 12x, and place the result next to 3x³. Result = -8x

5th step. Multiply 12x by -8x, change signs and place the result below -96x².

6th step. Add +96x² and -96x².

7th step. Divide 48x by 12x, and place the result next to the previous result.

8th step. Multiply 4 by 12x, change signs and place the result below 48x.

9th step. Add the results.

10th step. the result is 3x³ - 8x + 4

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4 years ago

Write an equation of the line that passes through the given point and is (a) parallel and (b) perpendicular to the given line.

Harrizon [31]

Answer:

Equation of the line that passes through the given point and is (a) parallel is: $\mathbf{y=-2x+11}$

Equation of the line that passes through the given point and is (b) perpendicular is: $\mathbf{y=\frac{1}{2}x+1}$

Step-by-step explanation:

We need to Write an equation of the line that passes through the given point and is (a) parallel and (b) perpendicular to the given line.

First we will find slope of the line given in graph

The slope can be found using formula: $Slope=\frac{y_2-y_1}{x_2-x_1}$

We have points (1,6) and (2,2)

Slope is:

$Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{2-6}{2-1}\\Slope=\frac{-4}{2}\\Slope=-2$

Part a)

Write an equation of the line that passes through the given point and is (a) parallel

When the lines are parallel, they have same slope. So, slope of required line: m = -2

Using slope m =-2 and point(4,3) we can find y-intercept b

$y=mx+b\\3=-2(4)+b\\3=-8+b\\b=3+8\\b=11$

The equation of line will be:

$y=mx+b\\y=-2x+11$

Equation of the line that passes through the given point and is (a) parallel is: $\mathbf{y=-2x+11}$

Part b)

Write an equation of the line that passes through the given point and is (b) perpendicular

When the lines are perpendicular they have opposite slope. So, slope of required line: m = 1/2

Using slope m =1/2 and point(4,3) we can find y-intercept b

$y=mx+b\\3=\frac{1}{2}(4)+b\\3=2+b\\b=3-2\\b=1$

The equation of line will be:

$y=mx+b\\y=\frac{1}{2}x+1$

Equation of the line that passes through the given point and is (b) perpendicular is: $\mathbf{y=\frac{1}{2}x+1}$

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3 years ago

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Vera_Pavlovna [14]

Answer:try sin 14/x

Step-by-step explanation:

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3 years ago

Are these answers right

bixtya [17]

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3 years ago