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3 years ago

11

How does brainstorm,decide,work,enjoy help with motivation?

1 answer:

Assoli18 [71]3 years ago

6 0

Answer:

It helps because it gets you thinking. Personally, it would motivate me because that process itself is very helpful. Brainstorm will get you your idea, you can decide if you want to do it or not, then you work on it, and because you have the right attitude towards whatever you are working on, you'll enjoy it!

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How do I round 0.3 to the nearest thousandth

Luda [366]

0.3 is 3 tenths.
The order of "ths" is tenths, hundredths, thousandths.
Since there are no numbers after the 3, you simply have to add 2 zeros to make it 300 thousandths.

0.300<span />

6 0

3 years ago

Simone measures the width of one of cardboard strip as 1/2 yard. A second cardboard strip measures 5/6 yard in width. Estimate t

Zepler [3.9K]

Answer:

The correct option is C. About 1 on the side with the 1 on top and 4 on the bottom yard.

Step-by-step explanation:

Consider the provided information.

Simone measures the width of one of cardboard strip as 1/2 yard.

A second cardboard strip measures 5/6 yard in width.

We need to find the combined width.

The combined width of the cardboard strip:

$\frac{1}{2} + \frac{5}{6}=\frac{8}{6}=1\frac{1}{3}$

$1\frac{1}{3}$ is closer to $1\frac{1}{4}$ as compare to $1\frac{1}{2}$

Hence, the correct option is C. About 1 on the side with the 1 on top and 4 on the bottom yard.

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3 years ago

Add fractions with unlike denominators

stealth61 [152]

Answer:

1 5/12 i think im sorry if i get it wrong.

Step-by-step explanation:

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3 years ago

Examine the power.

Semenov [28]

Answer is 325 your welcome

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3 years ago

Read 2 more answers

Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

Andre45 [30]

Answer:

Option d) 5 to the power of negative 5 over 6 is correct.

$\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

ie, $5^\frac{\bf -5}{\bf 6}$

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{5^5}= 5^{\frac{-5}{6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

7 0

3 years ago