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3 years ago

Please help can someone answer thesequickly

Mathematics

1 answer:

Bingel [31]3 years ago

3 0

6. Answer: 3c 7 floz

Step-by-step explanation:

Conversion: 1 c = 8 floz

7c 3 floz ⇒ 6c 11floz

- 3c 4 floz ⇒ - 3c 4 floz

3c 7 floz

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7. Answer: 1 lb 13 oz

Step-by-step explanation:

Conversion: 1 lb = 16 oz

4 lb 4 oz ⇒ 3 lb 20 oz

- 2 lb 7 oz ⇒ - 2 lb 7 oz

1 lb 13 oz

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8. Answer: 4 T 1500 lb

Step-by-step explanation:

Conversion: 1 T = 2000 lb

7 T 200 lb ⇒ 6 T 2200 lb

- 2 T 700 lb ⇒ - 2 T 700 lb

4 T 1500 lb

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9. Answer: 1 d 18 h

Step-by-step explanation:

Conversion: 1 d = 24 h

7 d 12 h ⇒ 6 d 36 h

- 5 d 18 h ⇒ - 5 d 18 h

1 d 18 h

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10. Answer: 2 h 30 min

Step-by-step explanation:

3 h 42 min

- 1 h 12 min

2 h 30 min

You might be interested in

Given the Arithmetic series A1+A2+A3+A4 7 + 11 + 15 + 19 + . . . + 91 What is the value of sum?

aivan3 [116]

Answer:

The value of the sum is 1078

Step-by-step explanation:

* Lets revise how to find the sum of the arithmetic series

- In the arithmetic series there is a constant difference between each

two consecutive terms

- Ex:

# 4 , 9 , 14 , 19 , 24 , .......... (+ 5)

# 25 , 15 , 5 , -5 , -15 , .......... (-10)

- So if the first term is a and the constant difference between each two

consecutive terms is d, then

U1 = a , U2 = a + d , U3 = a + 2d , U4 = a + 3d , ..........

- Then the nth term is Un = a + (n - 1)d

- The sum of n terms is Sn = n/2[a + L] , where L is the last term in

the series

* Lets solve the problem

∵ The arithmetic series is 7 + 11 + 15 + 19 + ......................... + 91

∴ The first term (a) is 7

∴ The last term is (L) 91

- Lets find the constant difference

∵ 11 - 7 = 4 and 15 - 11 = 4

∴ The constant difference (d) is 4

- Lets find the sum of the series from 7 to 91

∵ Sn = n/2[a + L]

∵ a = 7 and L = 91

∴ Sn = n/2[7 + 91]

- We need to know how many terms in the series

∵ L is the last term and equals 91 lets find its position in the series

∵ Un = a + (n - 1)d

∵ a = 7 , d = 4 and Un = 91

∴ 91 = 7 + (n - 1)(4) ⇒ subtract 7 from both sides

∴ 84 = (n - 1)(4) ⇒ divide both sides by 4

∴ 21 = n - 1 ⇒ add 1 to both sides

∴ n = 22

∴ The number of the terms in the series is 22

- Lets find the sum of the 22 terms (S22)

∴ S22 = 22/2[7 + 91]

∴S22 = 11[98] = 1078

* The value of the sum is 1078

4 0

4 years ago

Is this problem correct?

Strike441 [17]

Answer:

Yes that is correct. B is correct.

Step-by-step explanation:

When you plug 0 in for x, the result is 3.

When you plug 1 in for x, the result becomes 1.

The equation matches up correctly.

f(x) = -2x + 3

#teamtrees #WAP (Water And Plant)

8 0

3 years ago

Read 2 more answers

.. Which of the following are the coordinates of the vertices of the following square with sides of length a?

atroni [7]

Option A: $O(0,0), S(0,a), T(a,a), W(a,0)$

Option D: $O(0,0), S(a,0), T(a,a), W(0,a)$

Step-by-step explanation:

Option A: $O(0,0), S(0,a), T(a,a), W(a,0)$

To find the sides of a square, let us use the distance formula,

$d=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}$

Now, we shall find the length of the square,

$\begin{array}{l}{\text { Length } O S=\sqrt{(0-0)^{2}+(a-0)^{2}}=\sqrt{a^{2}}=a} \\{\text { Length } S T=\sqrt{(a-0)^{2}+(a-a)^{2}}=\sqrt{a^{2}}=a} \\{\text { Length } T W=\sqrt{(a-a)^{2}+(0-a)^{2}}=\sqrt{a^{2}}=a} \\{\text { Length } O W=\sqrt{(a-0)^{2}+(0-0)^{2}}=\sqrt{a^{2}}=a}\end{array}$

Thus, the square with vertices $O(0,0), S(0,a), T(a,a), W(a,0)$ has sides of length a.

Option B: $O(0,0), S(0,a), T(2a,2a), W(a,0)$

Now, we shall find the length of the square,

$\begin{aligned}&\text { Length } O S=\sqrt{(0-0)^{2}+(a-0)^{2}}=\sqrt{a^{2}}=a\\&\text {Length } S T=\sqrt{(2 a-0)^{2}+(2 a-a)^{2}}=\sqrt{5 a^{2}}=a \sqrt{5}\\&\text {Length } T W=\sqrt{(a-2 a)^{2}+(0-2 a)^{2}}=\sqrt{2 a^{2}}=a \sqrt{2}\\&\text {Length } O W=\sqrt{(a-0)^{2}+(0-0)^{2}}=\sqrt{a^{2}}=a\end{aligned}$

This is not a square because the lengths are not equal.

Option C: $O(0,0), S(0,2a), T(2a,2a), W(2a,0)$

Now, we shall find the length of the square,

$\begin{array}{l}{\text { Length OS }=\sqrt{(0-0)^{2}+(2 a-0)^{2}}=\sqrt{4 a^{2}}=2 a} \\{\text { Length } S T=\sqrt{(2 a-0)^{2}+(2 a-2 a)^{2}}=\sqrt{4 a^{2}}=2 a} \\{\text { Length } T W=\sqrt{(2 a-2 a)^{2}+(0-2 a)^{2}}=\sqrt{4 a^{2}}=2 a} \\{\text { Length } O W=\sqrt{(2 a-0)^{2}+(0-0)^{2}}=\sqrt{4 a^{2}}=2 a}\end{array}$

Thus, the square with vertices $O(0,0), S(0,2a), T(2a,2a), W(2a,0)$ has sides of length 2a.

Option D: $O(0,0), S(a,0), T(a,a), W(0,a)$

Now, we shall find the length of the square,

$\begin{aligned}&\text { Length OS }=\sqrt{(a-0)^{2}+(0-0)^{2}}=\sqrt{a^{2}}=a\\&\text { Length } S T=\sqrt{(a-a)^{2}+(a-0)^{2}}=\sqrt{a^{2}}=a\\&\text { Length } T W=\sqrt{(0-a)^{2}+(a-a)^{2}}=\sqrt{a^{2}}=a\\&\text { Length } O W=\sqrt{(0-0)^{2}+(a-0)^{2}}=\sqrt{a^{2}}=a\end{aligned}$

Thus, the square with vertices $O(0,0), S(a,0), T(a,a), W(0,a)$ has sides of length a.

Thus, the correct answers are option a and option d.

8 0

3 years ago

15 POINTS I REALLY NEED HELP!!!!!!!!!!!!!!!!!!!!!The solution to 16x = 48 is x = ___. (Only input the number.) Numerical Answers

AlexFokin [52]

Hello there, and thank you for asking your question here on brainly.

Short answer: 3

Why?

You can find this out by dividing 48 and 16. The number you get from it is how much 16s are in 48, which is the answer to our question. (48 / 16 ==> 3) Check: 16 * 3 = 48. This is correct.

Hope this helped you! ♥

6 0

3 years ago

Read 2 more answers

In a basketball game tamara made 16 out of 20 shots from the free throw line what percent did her shots make

den301095 [7]

Answer:80% of shots

Step-by-step explanation:

Divide 16 and 20 by 2

8 and 10

10 is total and 8 is how much she made therefore 80% of shots were made by Tamara.

7 0

3 years ago