The constant terms are: -14, and +2
It has been a while since I had done these, but I believe you need to multiply all the measurements together
Answer:
Both are inverse pairs
Step-by-step explanation:
Question 11

(a) Rename g(x) as y

(b) Solve for x :

(c) Multiply each side by ⅝

(d) Switch x and y

(e) Rename y as the inverse function

(f) Compare with your function

f(x) and g(x) are inverse functions.
The graphs of inverse functions are reflections of each other across the line y = x.
In the first diagram, the graph of ƒ(x) (blue) is the reflection of g(x) (red) about the line y = x (black)
Question 12
h(x)= x - 2
(a) Rename h(x) as y
y = x - 2
(b) Solve for x:
x = y + 2
(c) Switch x and y
y = x + 2
(e) Rename y as the inverse function
h⁻¹(x) = x + 2
(f) Compare with your function
f(x) = x + 2
f(x) = h⁻¹(x)
h(x) and ƒ(x) are inverse functions.
The graph of h(x) (blue) reflects ƒ(x) (red) across the line y = x (black).
Answer:
six uniys to left of 3 is= +2,+1,0,-1-2-3
three unit right of 15is= +16,+17, +18
Eight unit to the left of =-4,-5,-6,-8,-9,-10,-11,-12
seven units ti right of -5=-3,-2,-1,0+1,+2,+3,+4
4 + 5z = 5z + 4 is an identity and is true for all values of z.
The equation has, therefore, infinitely many solutions.