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xeze [42]
4 years ago
12

FRACTIONS ::::::: 8/9 + 7/27 = ??

Mathematics
2 answers:
mixas84 [53]4 years ago
8 0
To add, you must find a common denominator the two fractions.To do this, you must find the LCM of 9 and 27.
9:9,18,27
27:27,
The LCM is 27. Now, what times 9 is 27? 3. So, you have to multiply the numerator by 3 to get a fraction of 24/27. Now add! 24/27+7/27=31/27 or 1 and 4/27. Hope this helped!
sammy [17]4 years ago
4 0

Hello there ....

To get the answer, we must do the following to get it:
1.) Find the LCM.
9,18,27
27
The lcm we got is 27... make it your new denominator.

- 8/9 + 7/27 = ?/27 + ?/27 =

2.) Next is, divide the new denominator by the 9 on the 8/9..
= 3
Then, divide the new denominator again by the 27 on the 7/27.
= 1

3.) Multiply the no. you divided by the numberator of 8 by 8/9
=24/27
Then, multiply the no. again you divided by the numerator of 7 by 7/27
=7/27

4.) Add it up.

24/27 + 7/27 = 31/27 ...

It is an improper fraction so we wil just have to divide it.

31 ÷ 27

1 4/27 is the answer to your question.

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mrs_skeptik [129]

9514 1404 393

Answer:

  10.49

Step-by-step explanation:

Since we know 110 = 10² +10, we can make a first approximation to the root as ...

  √10 ≈ 10 +10/21 . . . . . where 21 = 1 + 2×integer portion of root

This is a little outside the desired approximation accuracy, so we need to refine the estimate. There are a couple of simple ways to do this.

One of the best is to use the Babylonian method: average this value with the value obtained by dividing 110 by it.

  ((220/21) + (110/(220/21)))/2 = 110/21 +21/4 = 881/84 ≈ 10.49

An approximation of √110 accurate to hundredths is 10.49.

__

The other simple way to refine the root estimate is to carry the continued fraction approximation to one more level.

For n = s² +r, the first approximation is ...

  √n = s +r/(2s+1)

An iterated approximation is ...

  s + r/(s +(s +r/(2s+1)))

The adds 's' to the approximate root to make the new fraction denominator.

For this root, the refined approximation is ...

  √110 ≈ 10 + 10/(10 +(10 +10/21)) = 10 +10/(430/21) = 10 +21/43 ≈ 10.49

_____

<em>Additional comment</em>

Any square root can be represented as a repeating continued fraction.

  \displaystyle\sqrt{n}=\sqrt{s^2+r}\approx s+\cfrac{r}{2s+\cfrac{r}{2s+\dots}}

If "f" represents the fractional part of the root, it can be refined by the iteration ...

  f'=\dfrac{r}{2s+f}

__

The above continued fraction iteration <em>adds</em> 1+ good decimal places to the root with each iteration. The Babylonian method described above <em>doubles</em> the number of good decimal places with each iteration. It very quickly converges to a root limited only by the precision available in your calculator.

4 0
3 years ago
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Sunny_sXe [5.5K]

Answer:

1. AB ~= DF

2. Definition of Congruent

3. Reflexive Property of Congruency

4 BD=BD

6. AB+BD=AD; DF+BD=BF

7. Substitution Property of Equality

8. Definition of Congruent

Step-by-step explanation:

1. The given always goes first, and that's the first reason, so AB ~= DF must be the first statement (that should be the congruency symbol).

2. The definition of congruent is that if they are congruent then they are equal. Since that statement made two congruent lines equal, it must be the definition.

3. The reflexive property means something is congruent to itself, and BDis BD, therefore it is the reflexive property.

4. Remember if something is congruent then it is equal.

6. The segment addition postulate states that if we are given two points on a line segment, then AB+AC=AC.

7. In this statement AD was substituted for DF+BD. This can be done because of AB=DF and BD=BD as aforementioned.

8. If two things are congruent then they are equal by definition of congruency.

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