Ask question

Ask question

All categories

3 years ago

12

FRACTIONS ::::::: 8/9 + 7/27 = ??

2 answers:

mixas84 [53]3 years ago

8 0

To add, you must find a common denominator the two fractions.To do this, you must find the LCM of 9 and 27.
9:9,18,27
27:27,
The LCM is 27. Now, what times 9 is 27? 3. So, you have to multiply the numerator by 3 to get a fraction of 24/27. Now add! 24/27+7/27=31/27 or 1 and 4/27. Hope this helped!

sammy [17]3 years ago

4 0

Hello there ....

To get the answer, we must do the following to get it:
1.) Find the LCM.
9,18,27
27
The lcm we got is 27... make it your new denominator.

- 8/9 + 7/27 = ?/27 + ?/27 =

2.) Next is, divide the new denominator by the 9 on the 8/9..
= 3
Then, divide the new denominator again by the 27 on the 7/27.
= 1

3.) Multiply the no. you divided by the numberator of 8 by 8/9
=24/27
Then, multiply the no. again you divided by the numerator of 7 by 7/27
=7/27

4.) Add it up.

24/27 + 7/27 = 31/27 ...

It is an improper fraction so we wil just have to divide it.

31 ÷ 27

1 4/27 is the answer to your question.

You might be interested in

The lowest temperature ever recorded in the U.S. was - 79.8 degrees Fahrenheit in Prospect Creek, Alaska. Which of the following

BabaBlast [244]

Answer:

D

Step-by-step explanation:

Negative numbers are less than zero.

3 0

3 years ago

Can you plz help me I don't understand this

Lana71 [14]

Add up all the rainfall amounts and divide by 11

6 0

3 years ago

Read 2 more answers

In the inequality 6a+4b>10, what could be the possible value of a if b=2?

Arlecino [84]

We are given the following inequality:

$6a+4b>10$

If we replace b = 2, we get:

$\begin{gathered} 6a+4(2)>10 \\ 6a+8>10 \end{gathered}$

Now we solve for "a" first by subtracting 8 on both sides:

$\begin{gathered} 6a+8-8>10-8 \\ 6a>2 \end{gathered}$

Now we divide both sides by 6

$\frac{6a}{6}>\frac{2}{6}$

Simplifying:

$a>\frac{1}{3}$

Therefore, for b = 2, the possible values of "a" are those that are greater than 1/3

3 0

1 year ago

If you want to be 95% confident of estimating the population mean to within a sampling error of plus or minus3 and the standard

Aleksandr [31]

Answer:

The sample size required is at least 171

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

What sample size is required?

A samle size of at least n is required, in which n is found when $M = 3, \sigma = 20$

So

$M = z*\frac{\sigma}{\sqrt{n}}$

$3 = 1.96*\frac{20}{\sqrt{n}}$

$3\sqrt{n} = 20*1.96$

$\sqrt{n} = \frac{20*1.96}{3}$

$(\sqrt{n})^{2} = (\frac{20*1.96}{3})^{2}$

$n = 170.7$

Rouding up

The sample size required is at least 171

5 0

3 years ago

What is the first quartile, Q1, of the data set?

Kryger [21]

It is 28 because you have to take the median out then go to the first set of data and find the median of that.

4 0

3 years ago