The answer is 79 and 80.
x - the number of the first locker
x + 1 - the number of the consecutive locker
Their sum is 159.
x + x + 1 = 159
2x + 1 = 159
2x = 159 - 1
2x = 158
x = 158 / 2
x = 79
x - the number of the first locker: x = 79
x + 1 - the number of the consecutive locker x + 1 = 79 + 1 = 80
Answer:
B
Step-by-step explanation:
Hi there!
We're given the measure of <AOC (the big angle) as 90°
and the measure of <BOC as 14° and the measure of <AOB as (3x+46)°
we want to find the value of what x is
because of angle addition postulate, m<AOC=m<BOC+m<AOB
so we can substitute our known values into that equation
90°=14°+3x°+46°
our goal is to isolate the variable of x onto one side
add 14 and 46 together
90°=3x°+60°
subtract 60° from both sides
30°=3x°
divide both sides by 3
10°=x
therefore B is your answer
Hope this helps!
Answer:
True
Step-by-step explanation:
If it is a fraction like (3a-3b)/(3a+12b)
= [3(a-b)]/[3(a+4b)]
= (a-b)/(a+4b)
