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slavikrds [6]
3 years ago
5

Math assignment I need help ASAP

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
6 0

Answer:

Option B: -4 - 15x - 10 + 4x = -45

Step-by-step explanation:

The second step of the equation is to distribute 5 to the numbers in the parenthesis

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2add7 time 4 and add y
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What is ✓ 75 in simplified form?<br> O 5V5<br> 0 2573<br> O 3V 5<br> O 3V 25
faust18 [17]
It should be 5√3

Because 25 x 3 = 75

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3 years ago
calcular el valor de la fuerza desconocida en cada gráfico, si el sistema esta en equilibrio (les pongo coronita :c ayuda porfaa
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Answer:

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Step-by-step explanation:

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8 0
3 years ago
In a certain town, the amount of sulfur oxide in the air, S, in tons, is related to the town’s population, P, in people. The rel
Lady bird [3.3K]

Answer:

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

Step-by-step explanation:

Data provided in the question:

Relation between the amount of sulfur oxide in the air and the population as:

S² = 110P² + 20P + 600

Population growth rate, \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

Now,

change in sulfur oxide with time i.e \frac{\textup{dS}}{\textup{dt}}

differentiating the given relation with respect to time 't'

we have

2S\frac{\textup{dS}}{\textup{dt}} =  2\times110P\frac{\textup{dP}}{\textup{dt}}  + 20

at P = 100 and  \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

we have

2S\frac{\textup{dS}}{\textup{dt}} = 2 × 110 × 100 × 10 + 20

or

2S\frac{\textup{dS}}{\textup{dt}} = 220020

or

\frac{\textup{dS}}{\textup{dt}} = \frac{\textup{220020}}{\textup{2S}}

or

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

8 0
3 years ago
Зу+9=14
Anon25 [30]

Answer:

Constant(s) = 14,9

Coefficient = 3

Variable = y

6 0
3 years ago
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