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jonny [76]
3 years ago
12

The accepted value for the acceleration due to gravity is 9.8 m/s2. What factors do you think are responsible for the difference

between your experimental result and the accepted value?
Physics
1 answer:
kakasveta [241]3 years ago
3 0
It’s hard to perfectly measure the distance something travels, as well as the exact time it takes, making the results have some variation.
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A track is mounted on a large wheel that is free to turn with negligible friction about a vertical axis (Fig. 11-48).A toy train
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Answer:

0.166 rad/s

Explanation:

See attachment for calculations

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A volleyball is dropped from a cliff and a soccer ball is thrown upward from the same position. When each ball reaches the groun
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The question is whether the statement is true or false.

The answer if false.

Explanation:

It is exactly the opposite. The soccer ball will hit the ground with greater velocity.

Since the soccer ball is thrown upward, when it returns to the same heigth from which it was throwm it will have a velocity downward, which will make that the soocer ball reaches the ground at the bottom of the clif with greater velocity than the volleball.

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A person trying to lose weight should
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This is a very wierd question but I will answer.It is A

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An object is placed in front of a convex mirror with a radius of curvature of magnitude 10 cm. The mirror produces an image that
jek_recluse [69]

Answer:

u = - 20 cm

m =\frac{1}{5}

Given:

Radius of curvature, R = 10 cm

image distance, v = 4 cm

Solution:

Focal length of the convex mirror, f:

f = \frac{R}{2} = \frac{10}{2} = 5 cm

Using Lens' maker formula:

\frac{1}{f} = \frac{1}{u} + \frac{1}{v}

Substitute the given values in the above formula:

\frac{1}{5} = \frac{1}{u} + \frac{1}{4}

\frac{1}{u} = \frac{1}{5} - \frac{1}{4}

u = - 20 cm

where

u = object distance

Now, magnification is the ratio of image distance to the object distance:

magnification, m =\frac{|v|}{|u|}

magnification, m =\frac{|4|}{|-20|}

m =\frac{4}{20}

m =\frac{1}{5}

4 0
3 years ago
How does a real image differ from a virtual image?
Snezhnost [94]

Answer:

one contains datta that can take up hard drive or disc space weras a picture takes up space on walls or photo albums

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