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elena-s [515]
3 years ago
12

Which point or points on the image below show constructive interference of light? *

Physics
2 answers:
vampirchik [111]3 years ago
8 0
B and D hope im right :))
KatRina [158]3 years ago
7 0
I believe that it’s B and D
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Join not for bâd purpose​
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What type of material is found in the asthenosphere?
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Answer:

The correct answer is option C.

Explanation:

The layer below the lithosphere , the upper layer of the mantle of the earth with high heat pressure .It is made up of almost solid rocks but also flows not which indicates that it consist of viscoelastic fluid of molten rocks.This is because in some regions there can be presence of molten rocks.

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A 2.0-mm-long, 1.0-mmmm-diameter wire has a variable resistivity given by rho(x)=(2.5×10−6)[1+(x1.0m)2]Ωmrho(x)=(2.5×10−6)[1+(x1
Tresset [83]

Answer:

1.144 A

Explanation:

given that;

the length of the wire = 2.0 mm

the diameter of the wire = 1.0 mm

the variable resistivity R = \rho (x) =(2.5*10^{-6})[1+(\frac{x}{1.0 \ m})^2]

Voltage of the battery = 17.0 v

Now; the resistivity of the variable (dR) can be expressed as = \frac{\rho dx}{A}

dR = \frac{(2.5*10^{-6})[1+(\frac{x}{1.0})^2]}{\frac{\pi}{4}(10^{-3})^2}

Taking the integral of both sides;we have:

\int\limits^R_0  dR = \int\limits^2_0 3.185 \ [1+x^2] \ dx

R = 3.185 [x + \frac {x^3}{3}}]^2__0

R = 3.185 [2 + \frac {2^3}{3}}]

R = 14.863 Ω

Since V = IR

I = \frac{V}{R}

I = \frac{17}{14.863}

I = 1.144 A

∴  the current if this wire if it is connected to the terminals of a 17.0V battery = 1.144 A

8 0
3 years ago
A 2 microcoulomb charge is placed at a distance of 0.25 m away from a 3.6 microcoulomb charge. Describe the type of electrostati
EleoNora [17]

Answer: 1.04N

Explanation:

Given

q1 = 2*10^-6C

q2 = 3.6*10^-6C

r = 0.25m

k = 9*10^9

Magnitude of electrostatic force can be calculated by using coulomb's law. Coulomb's law states that, "the magnitude of the electrostatic force of attraction or repulsion between two point charges is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them."

F =(kq1q2) / r²

F = (9*10^9 * 2*10^-6 * 3.6*10^-6) / 0.25²

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All objects emit what radiation
Eduardwww [97]
If an object is not at Absolute Zero, then it is
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