A gaseous refrigerant undergoes compression when 150 j of work is done on it. if the internal energy of the gas increases by 120
1 answer:
The heat transferred is -30J
When the gas undergoes compression, work is done on the gas and its internal energy increases.
According to the first law of thermodynamics, the increase in internal energyΔU is the sum of the heat given to the gas ΔQ and the amount of work done on the gas ΔW
The work done on the gas is 150 J due to compression and the internal energy of the gas increases by 120 J.
Therefore, the heat given to the gas is given by,
Thus, an amount of heat equal to 30 J flows out of the system.
You might be interested in
Answer:
Explanation:
First, we write the equations of motion for each axis. Since the crate is sliding with constant speed, its acceleration is zero. Then, we have:
Where T is the tension in the rope, F is the force exerted by the first worker, f_k is the frictional force, N is the normal force and mg is the weight of the crate.
Since and
, we can rewrite the first equation as:
Now, we solve for and calculate it:
This means that the crate's coefficient of kinetic friction on the floor is 0.18.
Answer:
The pressure is
Explanation:
From the question we are told that
The volume of the container is
The mass of is
The root-mean-square velocity is
The root -mean square velocity is mathematically represented as
Now the ideal gas law is mathematically represented as
=>
Where n is the number of moles which is mathematically represented as
Where M is the molar mass of
So
=>
=>
=>
substituting values
=>
=>