A gaseous refrigerant undergoes compression when 150 j of work is done on it. if the internal energy of the gas increases by 120
1 answer:
The heat transferred is -30J
When the gas undergoes compression, work is done on the gas and its internal energy increases.
According to the first law of thermodynamics, the increase in internal energyΔU is the sum of the heat given to the gas ΔQ and the amount of work done on the gas ΔW
The work done on the gas is 150 J due to compression and the internal energy of the gas increases by 120 J.
Therefore, the heat given to the gas is given by,
Thus, an amount of heat equal to 30 J flows out of the system.
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Answer:
A point on the outside rim will travel 157.2 meters during 30 seconds of rotation.
Explanation:
We can find the distance with the following equation since the acceleration is cero (the disk rotates at a constant rate):
Where:
v: is the tangential speed of the disk
t: is the time = 30 s
The tangential speed can be found as follows:
Where:
ω: is the angular speed = 100 rpm
r: is the radius = 50 cm = 0.50 m
Now, the distance traveled by the disk is:
Therefore, a point on the outside rim will travel 157.2 meters during 30 seconds of rotation.
I hope it helps you!