A gaseous refrigerant undergoes compression when 150 j of work is done on it. if the internal energy of the gas increases by 120
1 answer:
The heat transferred is -30J
When the gas undergoes compression, work is done on the gas and its internal energy increases.
According to the first law of thermodynamics, the increase in internal energyΔU is the sum of the heat given to the gas ΔQ and the amount of work done on the gas ΔW
The work done on the gas is 150 J due to compression and the internal energy of the gas increases by 120 J.
Therefore, the heat given to the gas is given by,
Thus, an amount of heat equal to 30 J flows out of the system.
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Answer:
a) [volts] = [N m / C],
b) The lines or surface that has the same potential are called equipotential
c) the equipotential lines must also be perpendicular to the electric field lines
Explanation:
a) find the units of the volt
the electric potential energy is
V = k q / r
V = [N m² / C²] C / m
V = [N m / C]
The electric potential is defined as
V = E .s
V = [N / C] [m]
V = [N m / C] = [volt]
we see that in the two expressions the same result is obtained therefore the volt is
[volts] = [N m / C]
b) The lines or surface that has the same potential are called equipotential surfaces, the great utility of these lines or surfaces is that a face can be displaced on it without doing work.
c) The electric potential is defined as the gradient of the electric field
v =
therefore the equipotential lines must also be perpendicular to the electric field lines
Answer:
Frequency, f = 1 unit
Explanation:
It is given that,
Period of the wave, T = 1 unit
We need to find the frequency of the wave. There exist an inverse relationship between period and the frequency of the wave. It is given by :
Or
f = 1 unit
So, the frequency of the wave is 1 unit. Hence, this is the required solution.