You will have to use this formula:
Final Velocity (V) = 4m/s
Initial Velocity (Vo) = 8m/s
Acceleration (a) = ? m/s^2
Time (t) = 2 secs
Then:
-> 4 = 8 + a x 2
-> 4 - 8 = 2a
-> -4 = 2a
-> a = -4/2
-> a = -2 m/s^2
Ps: It's value is negative because the she was in retrograde motion.
Answer: Her acceleration is -2 m/s^2.
To find the work done on the particle, the following is the
solution:
Dw = F dx
W = integral over the path ( F(x) dx)
W = integral from 0 to 1 (e^(-x/5 + 5) dx)
W = -5e^(-x/5 + 5) from 0 to 1
W = 135 J
The work done is 135 J.
The court of international trade, because tariffs are taxes upon trade
Answer:
thanks for the points liar
Explanation:
Answer:
(a) increase
Explanation:
On a line graph; we have the x-axis to the positive side and the negative side .In a positive x-axis direction, the force is usually positive, vice versa the negative side as well.
The change in the potential energy of a charge field-system can be given as:
where;
q = positive test charge
E = Electric field
ds = displacement between thee charge positions
θ = Angle between the electric field and the displacement.
Given that:
Charge of the particle = -q
displacement = (60.0 -20.0)cm = 40.0 cm
θ = 0
Replacing our values in the above equation, we have:
Since the potential energy of the system is positive, therefor the electric potential energy also increases.
