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Vsevolod [243]
2 years ago
9

Which title goes with this list: Amendments Articles Preamble?

Physics
1 answer:
anastassius [24]2 years ago
8 0
D. City and U.S. Government, but I’m not sure what the context is though.
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Following are the different layers of the Sun's atmosphere. Rank them based on the order in which a probe would encounter them w
Ghella [55]

Answer:

Sequence of layers to encounter while travelling from Earth to the surface of the sun are:

Option (A) - Corona

Option (C) - Chromosphere

Option (B) - Photosphere

Explanation:

  • Corona- It represents the extreme outer region of the surface of the sun. It is normally not visible because of the light emitted from the sun. So it is difficult to be seen from the naked eye, but it can be seen during the time of total solar eclipse. The temperature in this region is about several million degrees.
  • Chromosphere- It is a layer that lies between the Corona and the Photosphere. This layer has a thickness of about 2000 kilometers and the temperature in this layer ranges from about 6000°C to 20,000°C.
  • Photosphere- This layer is the bright visible layer of the sun which is comprised of plasma and dark and cool sunspots, that forms on the sun due to the emerging of the magnetic field of the sun from its surface.

Thus, the correct sequences are mentioned above.

3 0
2 years ago
PHYSICAL SCIENCE : What are the advantages and disadvantages of using nuclear energy to generate electricity?
Gnesinka [82]

Nuclear energy is EXTREMELY ecofriendly, punching down any fossil fuels and even wind energy. It also is reliable, and has low emissions. However, nuclear energy is somewhat expensive and can go wrong, being dangerous to the environment and people. Along with this, uranium is finite and radioactive waste disposal is really bad.

4 0
3 years ago
You are performing a double slit experiment very similar to the one from DL by shining a laser on two nattow slits spaced 7.5 x
Blizzard [7]

Complete Question

You are performing a double slit experiment very similar to the one from DL by shining a laser on two nattow slits spaced 7.5 * 10^{-3} meters apart. However, by placing a piece of crystal in one of the slits, you are able to make it so that the rays of light that travel through the two slits are Ï out of phase with each other (that is to say, Ao,- ). If you observe that on a screen placed 4 meters from the two slits that the distance between the bright spot closest to center of the pattern is 1.5 cm, what is the wavelength of the laser?

Answer:

The  wavelength is  \lambda  =  56250 nm

Explanation:

From the question we are told that

   The  distance of slit separation is  d =  7.5 *10^{-3} \  m

   The  distance of the screen is  D =  4 \  m

    The  distance between the bright spot closest to the center of the interference  is  k   = 1.5 \ cm = 0.015 \  m

   

Generally the width of the central  maximum fringe produced is mathematically represented as

        y  =  2 *  k  = \frac{ D  *  \lambda}{d}

  =>    2 *  0.015 =  \frac{ \lambda  *  4}{ 7.5 *10^{-3}}

   =>   \lambda  =  56250 *10^{-9} \ m

=>      \lambda  =  56250 nm

7 0
3 years ago
Name the net force between objects that allows a car to travel in a circle
iren [92.7K]
I think centripetal force ☺
6 0
3 years ago
a flag of mass 2.5 kg is supported by a single rope. A strong horizontal wind exerts a force of 12 N on the flag. Calculate the
tatuchka [14]
The free-body diagram of the forces acting on the flag is in the picture in attachment.

We have: the weight, downward, with magnitude
W=mg = (2.5 kg)(9.81 m/s^2)=24.5 N
the force of the wind F, acting horizontally, with intensity
F=12 N
and the tension T of the rope. To write the conditions of equilibrium, we must decompose T on both x- and y-axis (x-axis is taken horizontally whil y-axis is taken vertically):
T \cos \alpha -F=0
T \sin \alpha -W=
By dividing the second equation by the first one, we get
\tan \alpha =  \frac{W}{F}= \frac{24.5 N}{12 N}=2.04
From which we find
\alpha = 63.8 ^{\circ}
which is the angle of the rope with respect to the horizontal.

By replacing this value into the first equation, we can also find the tension of the rope:
T= \frac{F}{\cos \alpha}= \frac{12 N}{\cos 63.8^{\circ}}=27.2 N




7 0
3 years ago
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