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creativ13 [48]
4 years ago
10

Propane (C3H8) reacts with oxygen (O2) during a combustion reaction, producing carbon dioxide

Chemistry
1 answer:
Over [174]4 years ago
8 0

Answer:

C3H8 + 5 O2 ------> 3 CO2 + 4 H2O

Explanation:

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1. Factorise<br>3х<br>- 10x +8​
lara [203]

Answer:

This question is incomplete, it should read 3x² - 10x + 8. The answer is (3x-4) (x-2).

Please find the solved explanation to this question attached

Explanation:

To factorize means to write an expression as a product of its factors using brackets. It is the opposite of expanding an algebraic expression i.e. it involves contracting it using factors common to the variables.

In this question, 3x² - 10x + 8 is given

For the sum, which is -10x, and product, which is 24x², -6x and -4x are the two variables whose sum will give rise to -10x and also whose product will give rise to 24x².

We have;

3x² - 10x + 8

3x² - 6x - 4x + 8

Next, we look for factors of each pair of expression.

3x (x - 2) - 4 (x - 2)

(3x - 4) (x - 2)

3 0
3 years ago
Which electrons are the valence electrons of the atom?
Veronika [31]

Valence electrons are the electrons in the outermost shell, or energy level, of an atom. For example, oxygen has six valence electrons, two in the 2s subshell and four in the 2p subshell. We can write the configuration of oxygen's valence electrons as 2s²2p⁴
6 0
3 years ago
Please help me this is my fourth attempt.
Vaselesa [24]

Explanation:

CH4 + 4S ---> CS2 + 2H2S

4) 0.75 mol S × (1 mol CS2/4 mol S) = 0.19 mol CS2

5) 3 mol H2S × (1 mol CH4/2 mol H2S) = 1.5 mol CH4

Fe2O3 + 2Al ---> 2Fe + Al2O3

6) 25 g FeO3 × (1 mol Fe2O3/159.69 g Fe2O3) = 0.16 mol Fe2O3

0.16 mol Fe2O3 × (2 mol Al/1 mol Fe2O3) = 0.32 mol Al

0.32 mol Al × (26.98 g Al/1 mol Al) = 8.6 g Al

7) Given:

45 g Al × (1 mol Al/26.98 g Al) = 1.6 mol Al

85 g Fe2O3 ×(1 mol Fe2O3/159.69 g Fe2O3)

= 0.53 mol Fe2O3

Let's look at how much Fe each reactant will produce:

1.6 mol Al × (2 mol Fe/2 mol Al) = 1.6 mol Fe

0.53 mol Fe2O3 × (2 mol Fe/1 mol Fe2O3) = 1.1 mol Fe

Note that the given amount of Fe2O3 will give us fewer Fe. Therefore, Fe2O3 is the limiting reactant.

8) Al will produce 1.6 mol Fe × (55.845 g Fe/1 mol Fe)

= 89 g Fe

Fe2O3 will produce 1.1 mol Fe × (55.845 Fr/1 mol Fe)

= 61 g Fe

9) Since Fe2O3 is the limiting reactant, the ideal yield of Fe for the reaction is 61 g. If the actual reaction only gave us 25 g Fe. then the percent yield of Fe is

%yield = (25 g Fe/61 g Fe) × 100% = 41%

10) If we only got 25 g Fe, then the amount of Al actually used in the reaction is

25 g Fe × (1 mol Fe/55.845 g Fe) = 0.45 mol Fe

0.45 mol Fe × (2 mol Al/2 mol Fe) = 0.45 mol Al

0.45 mol Al × (26.98 g Al/1 mol Al) = 12 g

Therefore, the leftover amount of Al is

25 g Al - 12 g Al = 13 g Al

8 0
3 years ago
Which is the answer please help
djyliett [7]

Answer:

The outermost energy shell of an atom likes to be full with 8 electons

Explanation:

4 0
3 years ago
Read 2 more answers
575 394 9550<br> bFzN0S<br> come study with me!
Rina8888 [55]

Answer:

im good thxs for offering tho!

Explanation:

7 0
3 years ago
Read 2 more answers
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