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vlada-n [284]
3 years ago
10

Formaldehyde (h2co) reacts with oxygen to form co2 and h2o. how many moles of co2 will be produced from reacting 2 moles of h2co

with oxygen?
Chemistry
2 answers:
bogdanovich [222]3 years ago
7 0
Answer:
            2 mol of CO₂

Solution:

The reaction is as follow,

                              H₂CO  +  O₂     →     CO₂  +  H₂O

According to this equation,

                         1 mole of H₂CO produces  =  1 mole of CO₂
So,
                   2 moles of H₂CO will produce  =  X moles of CO₂

Solving for X,
                      X  =  (2 mol × 1 mol) ÷ 1 mol

                      X  =  2 mol of CO₂
NARA [144]3 years ago
3 0
<h2>Answer:</h2>

<u>2 moles</u><u> of CO2 will be produced</u>

<h2>Explanation:</h2>

Chemical equation for the reaction will be

Formaldehyde + oxygen → CO₂ + H₂O

H₂CO + O₂ → CO₂ + H₂O

Since the equation is already balanced so

Taking the mole ratios

1 mol H₂CO : 1 mol O₂ : 1 mol CO₂ : 1 mol H₂O

We can see that every mole of H₂CO produces 1 moles of CO₂ , which means that 2 moles of CO₂ are produced from reacting 2 moles of H₂CO with oxygen.

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Which of these phrases accurately describe disproportionation? Check all that apply.
Olin [163]

Answer:

A single compound is simultaneously oxidized and reduced.

Explanation:

In chemistry, disproportionation is a simultaneous oxidation and reduction of a single chemical specie.

What this means is that; in a disproportionation reaction, only one compound is both oxidized and reduced. This implies that two products are formed during disproportionation. One is the oxidized product while the other is the reduced product.

Consider the disproportionation of CuCl shown below;

2CuCl -----> CuCl2 + Cu

Here, CuCl2 is the oxidized product while Cu is the reduced product.

7 0
2 years ago
Read 2 more answers
Calculate the pH of a solution created by placing 2.0 grams of yttrium hydroxide, Y(OH)3, in 2.0 L of H2O. Ksp for Y(OH)3 is 6.0
oee [108]

Answer:

pH = 8.314

Explanation:

  • Y(OH)3(s) ↔ Y+  +  3OH-

equil:   S               S         3S

∴ Ksp = [ Y+ ] * [ OH- ]³ = 6.0 E-24

⇒ 6.0 E-24 = ( S )*( 3S )³

⇒ 6.0 E-24 = 27S∧4

⇒ 2.22 E-25 = S∧4

⇒ ( 2.22 E-25 )∧(1/4) = S

⇒ S = 6.866 E-7 M

⇒ [ OH- ] = 3*S =2.06 E-6 M

⇒ pOH = - Log [ OH- ]

⇒ pOH = - Log ( 2.06 E-6 )

⇒ pOH = 5.686

∴ pH = 14 - pOH

⇒ pH = 8.314

8 0
3 years ago
What is the number of molecules of c2h5oh in a 3m solution that contains 4.00kg h2o?
Veronika [31]
 The number  of C2H5OH  in a 3 m solution that contain 4.00kg H2O is calculate as below

M = moles of the solute/Kg  of water

that is 3M = moles of solute/ 4 Kg
multiply  both side by  4

moles of the  solute  is therefore = 12  moles

by use of Avogadro law constant

1 mole =6.02 x10^23  molecules

what  about 12 moles

=12 moles/1 moles  x 6.02 x10^23 = 7.224 x10^24 molecules
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3 years ago
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562 grams because mass can not be created or destroyed
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