This is a probability problem with two dependent events and conditional probability. Note that after the first donut is chosen, it is not replaced into the data set, so only 23 donuts remain. If we set A=selection of a lemon-filled, and B=selection of a custard-filled, then P(A and B) = P(A)*P(B|A), where P(B|A) means the probability of B happening given that A has already occurred.P(A) = 8/24 = 1/3 = 0.333333P(B|A) = 12/23 = 0.521739P(A and B) = 1/3(12/23) = 12/69 = 0.1739130435 or 17.4%
https://www.wyzant.com/resources/answers/296921/find_the_probability_of_selecting_a_a_lemon_filled_d...
X> 1000/997
Alternate form is
x> 10 30/997, 1000/997 = 10.03009 , x {10000/997 , + infinity}
Hey there!
You got the first part right where you added r to both sides. However, you need to make sure that you complete all actions on both sides, including canceling out parts of terms by division. The only thing you need to do is divide both sides by h instead of just the left. This will make your answer:

Hope this helped you out! :-)
Answer:
the first step is to use the
✔ Subtraction
property of equality to combine the constant terms.
The second step is to use the
✔ Division
property of equality to isolate the variable
Step-by-step explanation:
edge 20 20