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Damm [24]
3 years ago
9

3x-7y=14

Mathematics
1 answer:
Mademuasel [1]3 years ago
4 0

Answer:

A. \frac{3}{7}

Step-by-step explanation:

The given equation is

3x-7y=14

We solve for y by  subtracting 3x from both sides to obtain;

-7y=14-3x

We now divide through by -7 to get;

y=\frac{-3}{-7}x+\frac{14}{-7}

This simplifies to;

y=\frac{3}{7}x-2

This equation is now in the form y=mx +c, where m=\frac{3}{7} is the slope.

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Evgesh-ka [11]

Solution given:

\sin( \alpha )  =   \frac{\sqrt{5} }{3}

so

P=√5

h=3

b=\sqrt{3 {}^{2} -  \sqrt{5}  {}^{2}  }

b=2

so

\cos( \alpha )  =  \frac{b}{h}  =  \frac{2}{3}

Note

\alpha  = 0

<u>b</u><u>:</u><u>⅔</u>

8 0
2 years ago
Find the missing side lengths
timama [110]

since this a 45 45 90 right triangle to get the side lengths you divide 2 times the square root of 2 and you get 2, since this has two congruent angles which makes it an Isosceles triangle. your a and b value are 2.

8 0
3 years ago
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Eduardwww [97]

Answer:

3. 4 meters

6. wrong, it should be 7000 meters

7. 2 dm > 10 cm

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Step-by-step explanation:

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6 0
3 years ago
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What is the range for the possible side length AB of ABC?
julia-pushkina [17]

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Step-by-step explanation:

5 0
2 years ago
I'm not sure where to start and how to differentiate this.
Mazyrski [523]
The picture is not clear. let me assume y = (x^4)ln(x^3)

product rule :
d f(x)g(x) = f(x) dg(x) + g(x) df(x)

dy/dx = (x^4)d[ln(x^3)/dx] + d[(x^4)/dx] ln(x^3)
= (x^4)d[ln(x^3)/dx] + 4(x^3) ln(x^3)

look at d[ln(x^3)/dx]
d[ln(x^3)/dx]
= d[ln(x^3)/dx][d(x^3)/d(x^3)]
= d[ln(x^3)/d(x^3)][d(x^3)/dx]
= [1/(x^3)][3x^2] = 3/x
... chain rule (in detail)

end up with
dy/dx = (x^4)[3/x] + 4(x^3) ln(x^3)
= x^3[3 + 4ln(x^3)]

5 0
3 years ago
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