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svet-max [94.6K]
3 years ago
14

Solve for the variable in the following equation.

d="TexFormula1" title=" \frac{x}{8} = 13" alt=" \frac{x}{8} = 13" align="absmiddle" class="latex-formula">
Please hurry​
Mathematics
1 answer:
LenaWriter [7]3 years ago
6 0

x=104 is the correct answer

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In ΔLMN, \overline{LN}
Karolina [17]

Answer:

\bold{\angle NLM = 10^\circ}

Step-by-step explanation:

Given a ΔLMN.

Line LN is extended to point O.

such that:

\text{m}\angle MNO = (5x-13)^{\circ}

\text{m}\angle NLM = (x-4)^{\circ} and

\text{m}\angle LMN = (2x+19)^{\circ}

To find:

\text{m}\angle NLM=?

Solution:

Kindly refer to the attached image for the given triangle and dimensions of angles.

Let us recall the external angle property of a triangle:

The external angle of a triangle is equal to the sum of two opposite internal angles.

i.e.

\angle MNO = \angle NLM + \angle LMN\\\Rightarrow 5x-13 = x-4+2x+19\\\Rightarrow 5x-13 = 3x+15\\\Rightarrow 5x-3x = 13+15\\\Rightarrow 2x=28\\\Rightarrow x =14

Putting the value of x in \angle NLM.

\angle NLM=14-4 \\\Rightarrow \bold{\angle NLM = 10^\circ}

5 0
3 years ago
Simplify the expression (7x² - 3x) + (11x² - x - 7) A. 18x² + 2x + 7 B. 4x² - 4x - 7 C. 18x² - 2x - 7 D. 18x² - 4x - 7
IRINA_888 [86]

Answer: D.

Step-by-step explanation:

7 0
3 years ago
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Raj’s farmhouse is 1245km away from hiswarehouse. Daily he drivesa certain distance and then his friend Rohantakes aturn to driv
mariarad [96]

Answer:

Step-by-step explanation:

Subtract the distance driven by Rohan from the total distance

Distance driven by Raj = 1245 - 412

                                     = 833 km

8 0
3 years ago
What is the value of y in the equation 2(3y + 6 + 3) = 196 − 16?
Vlad [161]
The answer is 27, I had it on a test.
6 0
3 years ago
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Let f(x)=4x-1 and g(x)=2x^2+3. Perform each function operations and then find the domain.
Triss [41]
F(x) = 4x - 1
g(x) = 2x² + 3

1. (f + g)(x) = (4x - 1) + (2x² + 3)
    (f + g)(x) = 2x² + 4x + (-1 + 3)
    (f + g)(x) = 2x² + 4x + 2
    Domain: {x| -∞ < x < ∞}, (-∞, ∞)

2. (f - g)(x) = (4x + 1) - (2x² + 3)
    (f - g)(x) = 4x + 1 - 2x² - 3
    (f - g)(x) = -2x² + 4x + 1 - 3
    (f - g)(x) = -2x² + 4x - 2
    Domain: {x|-∞ < x < ∞}, (-∞, ∞)
3. (g - f)(x) = (2x² + 3) - (4x - 1)
    (g - f)(x) = 2x² + 3 - 4x + 1
    (g - f)(x) = 2x² - 4x + 3 + 1
    (g - f)(x) = 2x² - 4x + 4
    Domain: {x| -∞ < x < ∞}, (-∞, ∞)

4. (f · g)(x) = (4x + 1)(2x² + 3)
    (f · g)(x) = 4x(2x² + 3) + 1(2x² + 3)
    (f · g)(x) = 4x(2x²) + 4x(3) + 1(2x²) + 1(3)
    (f · g)(x) = 8x³ + 12x + 2x² + 3
    (f · g)(x) = 8x³ + 2x² + 12x + 3
    Domain: {x| -∞ < x < ∞}, (-∞, ∞)

5. (\frac{f}{g})(x) = \frac{4x - 1}{2x^{2} + 3}
    Domain: 2x² + 3 ≠ 0
                         - 3  - 3
                        2x² ≠ 0
                         2      2
                          x² ≠ 0
                           x ≠ 0
                  (-∞, 0) ∨ (0, ∞)

6. (\frac{g}{f})(x) = \frac{2x^{2} + 3}{4x - 1}
    Domain: 4x - 1 ≠ 0
                      + 1 + 1
                        4x ≠ 0
                         4     4
                         x ≠ 0
                (-∞, 0) ∨ (0, ∞)
6 0
3 years ago
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