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Andrej [43]
3 years ago
9

Find the values of x when y = 1 y=x^2 -2x-3

Mathematics
1 answer:
alexandr402 [8]3 years ago
4 0
Yao’s a kma. Balkan a a
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Beginning at sunrise the temperature rose 2.8° per hour how long did it take for the temperature to rise a total of 19.18°?
nadezda [96]
19.18/2.8= 6.85 hours or rounded it would be 7 hours

3 0
3 years ago
Read 2 more answers
There are 325 children at the zoo . If 64% of children are boys and the
aleksandr82 [10.1K]

Answer:

117 Girls

Step-by-step explanation:

If 64% of the kids are boys, then 36% are girls   64% + 36% = 100%

.36 x 325 = 117  girls

Proof

.64 x 325 = 208 boys

208 + 117 = 325


4 0
3 years ago
What is 8 and 4/25 and as a mixed fraction or mixed number.
Sphinxa [80]

Answer:

Improper fraction for 8 4/25 is 204/25

Step-by-step explanation:

The numbers in the mixed fraction are defined as follow

8 = whole number

4 = numerator

25 = denominator

 Multiply the whole number by the denominator

8 × 25 = 200

Add the product from Step 1 to the numerator

200 + 4 = 204

Write answer from Step 2 over the denominator

204/25

The mixed number 8 4/25 converted to improper fraction is therefore :

3 0
3 years ago
Help asap!! need help alot!!
Neko [114]
Second answer: f - 52 = 63.
8 0
3 years ago
In a quality control test of parts manufactured at Dabco Corporation, an engineer sampled parts produced on the first, second, a
sammy [17]

Answer:

p value = 0.0174

Conclusion : we reject the null hypothesis

Step-by-step explanation:

Thinking step:

We need to perform a test to determine if the proportion of the good parts is the same for all three shifts at a significance level of \alpha = 0.05

Assumption : all the population for each or the three shifts is not equal.

Calculation:

Let p₁ be the sample of the first shift

     p₂ be the sample of the second shift

     p₃ be the sample of the third shift

According to the null hypothesis

H₀ = p₁ = p₂ = p₃

In other words, all the population sample proportions are equal.

Alternatively, we can assume that the three shift are not equal p₁ ≠ p₂ ≠ p₃

Tabulating and performing the \chi² test gives 8.10

degrees of freedom:

df = k - 1

   = 3 - 1 = 2

Thus the degree of freedom is 2

Solving using the MINITAB software gives: p = 0.174

The solution shows that the p value < level of significance, then p-value lies in the range 0.0174≤\alpha≤0.05

Therefore, we reject the null hypothesis based on the fact that the three shifts are not equal.

5 0
3 years ago
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