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3 years ago

PLEASE HELP! DUE AT 11:59 PST

Mathematics

1 answer:

Nesterboy [21]3 years ago

3 0

Answer:

Y = 15x + 30 and 8 hours

Step-by-step explanation:

She gets $15 per hour so her income is based on her hours, but we don't know what that is yet so, 15x.

She gets a solid $30 every week that is straight forward

To solve the function

150 = 15x + 30

subtract 30 from both sides

120 = 15x

divide 15 from both sides

8 = x

x = 8

You got this :)

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Identify the GCF of 6x2y2 − 8xy2 + 10xy3. 6x2y2 2x2y 2xy2 6xy2

sattari [20]

First find GCF of the numbers:-

GCF of 2, 6 and 8 = 2
GCF od x^2 x and x is x
GCF of y^2, y^2 and y^3 is y^2

so the answer is 2xy^2

The third choice.

3 0

3 years ago

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Can someone answer this?

ad-work [718]

Answer:

Step-by-step explanation:

6x-1+3x+5x+3+4x+8+5x+5=360 degree(sum of exterior angle of a pentagon is 360 degree)

23x+15=360

23x=360-15

x=345/23

x=15

therefore the value of x is 15 degree.

8 0

3 years ago

Mohamed decided to track the number of leaves on the tree in his backyard each year The first year there were 500 leaves Each ye

svetlana [45]

Answer:

The required recursive formula is

$f(n)= 500\times(1.4)^{n-1}\\$

Step-by-step explanation:

Mohamed decided to track the number of leaves on the tree in his backyard each year.

The first year there were 500 leaves

$Year \: 1 = 500$

Each year thereafter the number of leaves was 40% more than the year before so that means

$Year \: 2 = 500(1+0.40) = 500\times 1.4\\$

For the third year the number of leaves increase 40% than the year before so that means

$Year \: 3 = 500\times 1.4(1+0.40) = 500 \times 1.4^{2}\\$

Similarly for fourth year,

$Year \: 4 = 500\times 1.4^{2}(1+0.40) = 500\times 1.4^{3}\\$

So we can clearly see the pattern here

Let f(n) be the number of leaves on the tree in Mohameds back yard in the nth year since he started tracking it then general recursive formula is

$f(n)= 500\times(1.4)^{n-1}\\$

This is the required recursive formula to find the number of leaves for the nth year.

Bonus:

Lets find out the number of leaves in the 10th year,

$f(10)= 500\times(1.4)^{10-1}\\\\f(10)= 500\times(1.4)^{9}\\\\f(10)= 500\times20.66\\\\f(10)= 10330$

So there will be 10330 leaves in the 10th year.

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3 years ago

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A newspaper van made 8 stops in one neighborhood of apartments. By Stop 4, there had been 12 newspapers delivered.

Masja [62]

There would be 15 newspapers.

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3 years ago

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vfiekz [6]

Answer:reflect across

Step-by-step explanation:

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3 years ago