<span> (3•19x5)
Simplify ————————
19x2
</span>Dividing exponential expressions :
<span> 3.1 </span> <span> x5</span> divided by <span>x2 = x(5 - 2) = x3</span>
Canceling Out :
<span> 3.2 </span> Canceling out <span>19 </span> as it appears on both sides of the fraction line
Final result :<span> 3x<span>3</span></span>
Answer:
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Hope this helps!
The sum of first 20 terms of Arithmetic Series is 650 if the first term is 4 and the common difference is 3.
Step-by-step explanation:
First Term (a) = 4
Common difference (d) = 3
The number of term (n) = 20
The sum of an Arithmetic series of (n) number of terms, with first term (a) and the common difference (d) is equal to
Sum = (n/2) * ( 2 * a + (n -1) * d)
So putting the values of a,d, n
Sum = ( 20/2) * ( 2 * 4 + (20 -1) *3 )
Sum = (10) * ( 8 + 19 * 3)
Sum = 10 * ( 8 + 57)
Sum = 10 * 65 = 650
Hence the sum of first 20 terms of Arithmetic Series is 650 if the first term is 4 and the common difference is 3.
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