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Tpy6a [65]
3 years ago
14

An onsite oil change service charges a flat rate of $40.00 per service call and an additional $2.25 per mile fee for travel outs

ide a certain radius. Josh budgets $200 per year for oil changes on his vehicle. He lives 7 miles outside the radius. What is the greatest number of oil changes (c) that he can schedule and keep on budget for the year? A) 3 B) 4 C) 5 D) 6
Mathematics
2 answers:
Alexeev081 [22]3 years ago
5 0

The answer is 3.

55.75c ≤ 200

c ≤ 3.59

Maurinko [17]3 years ago
5 0

Answer:

The correct answer is option B,

Total four service can be taken.

Step-by-step explanation:

Distance traveled by Josh outside the radius 7 miles\\

The cost of travelling 7 miles\\ outside the radius

= 7 * 2.25\\= 15.75\\

The amount remaining after paying for the outside travelling

= 200 - 15. 75\\= 184.25\\

Number of oil service than can be taken out of the remaining amount

= \frac{184.25}{40} \\= 4.60\\

Thus total four service can be taken

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5. Identify the sign of the leading coefficient and describe the end behaviour. Using this
jek_recluse [69]

The sign of the leading coefficient can be found using the graph of a polynomial function.

<h3>What is polynomial?</h3>

Polynomial is the combination of variables and constants systematically with "n" number of power in ascending or descending order.

\rm a_1x+a_2x^2+a_3x^3+a_4x^4..........a_nx^n

We have given the graph of polynomial functions:

In the first graph:

The leading coefficient is positive.

x → ∞, f(x) → ∞

x → -∞, f(x) → -∞

Degree of a function = 3

In the second graph:

The leading coefficient is negative.

x → ∞, f(x) → -∞

x → -∞, f(x) → -∞

Degree of a function = 4

In the third graph:

The leading coefficient is positive.

x → ∞, f(x) → ∞

x → -∞, f(x) → ∞

Degree of a function = 4

In the fourth graph:

The leading coefficient is negative.

x → ∞, f(x) → -∞

x → -∞, f(x) → ∞

Degree of a function = 3

Thus, the sign of the leading coefficient can be found using the graph of a polynomial function.

Learn more about Polynomial here:

brainly.com/question/17822016

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5 0
2 years ago
Write an equation of the line that passes through (2, -5) and is parallel to the line 2y = 3x + 10
Zarrin [17]

First you get "y" by itself. To do so you divide 2 on both sides.

y = 3/2x + 5

To write an equation of a line that is PARALLEL to this equation, the slopes have to be the SAME. So the slope is 3/2.

You then use the equation:

y = mx + b

SInce you know "m" you plug it in.

y = 3/2x + b

Now you need to find b. To do so you plug in the point (2, -5) into this equation.

-5 = 3/2(2) + b

-5 = 3 + b

-8 = b

Finally you plug in b and you get your new equation.

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3 years ago
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3 years ago
Can somebody help me out i’m struggling really badly
zhuklara [117]
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6 0
3 years ago
This question has two parts. Be sure to answer both parts of the question. One inequality in a system is shown below. -12x + 3y
fgiga [73]

The inequality is -12x + 3y > 9.

PART A:

The sytem has no solution if inequality does not share a common area. The inequality -12x + 3y > 9 consist the region to left of line -12x + 3y = 9. So for no solution the region to left of equation -12x + 3y = 9 is suitable.

Thus inequality for no solution is, -12x + 3y < 9.

PART B:

For infinite solution the region of both inequality must overlap each other, or the inequality is same with some multiplication of divison factor. So inequality for infinite many solutions is,

\begin{gathered} (-12x+3y>9)\times-1 \\ 12x-3y

Thus inequality for infinite many solution is 12x - 3y < -9.

7 0
1 year ago
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